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Brilliant_brown [7]
3 years ago
11

Find a10 of the sequence 4, 28, 196, 1372

Mathematics
1 answer:
Naddik [55]3 years ago
6 0

Answer:

\purple { \bold{ a_{10}=161414428}}

Step-by-step explanation:

Given sequence is: 4, 28, 196, 1372

28/4 = 7

196/28 = 7

1372/196 = 7

Since, the ratio of any two consecutive terms is same, so it is a geometric sequence.

Therefore,

Common ratio r = 7

First term a = 4

nth term of a geometric sequence is given as:

a_n=ar^{n-1} \\  \\\implies  \\  \\ a_{10}=4.7^{10-1} \\  \\ a_{10}=4.7^{9} \\  \\ a_{10}=4.7^{9} \\  \\ a_{10}=4(40353607) \\  \\   \red{ \bold{ a_{10}=161414428}}

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