Question

Find a10 of the sequence 4, 28, 196, 1372

Answer 1

Answer:

$\purple { \bold{ a_{10}=161414428}}$

Step-by-step explanation:

Given sequence is: 4, 28, 196, 1372

28/4 = 7

196/28 = 7

1372/196 = 7

Since, the ratio of any two consecutive terms is same, so it is a geometric sequence.

Therefore,

Common ratio r = 7

First term a = 4

nth term of a geometric sequence is given as:

$a_n=ar^{n-1} \\ \\\implies \\ \\ a_{10}=4.7^{10-1} \\ \\ a_{10}=4.7^{9} \\ \\ a_{10}=4.7^{9} \\ \\ a_{10}=4(40353607) \\ \\ \red{ \bold{ a_{10}=161414428}}$