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nikklg [1K]
3 years ago
5

Which of the following are true?

Mathematics
1 answer:
Alex73 [517]3 years ago
8 0
D : because this make so much since duh . && watch yuu get it right !
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In a fraction with a denominator of 15, which value could the numerator be to produce a repeating decimal? A) 9 B) 11 C) 12 D) 1
Damm [24]
Out of the following choices, the value that could be the numerator to produce a repeating decimal is 12. The correct answer will be C .
4 0
3 years ago
If 7 beans were on your plate, and you took away 2 bananas, how many apples are left?
Tasya [4]

Answer:

4 tacos

Step-by-step explanation:

according to the converse of triangle proportionality theorem, 7 beans is equivalent to 5 bananas, so if we took 2 away we would be left with 4 tacos, not apples because an apple a day keeps the doctor away and we are in a pandemic right now

6 0
3 years ago
A company manufactures aluminum mailboxes in the shape of a box with a half-cylinder top. The company will make 1960 mailboxes t
MaRussiya [10]

Answer:

  7088 m²

Step-by-step explanation:

The area of the half-cylinder is half the area of a cylinder with the same dimensions. This half-cylinder has a radius of 0.3 m and a length of 0.8 m, so its area is ...

  A = πr(r +l) = π(0.3 m)(0.3 m+0.8 m) = 0.33π m² ≈ 1.0362 m²

The area of the bottom part of the box is the sum of its lateral area and its base area.

  lateral area = Ph = (2(0.6m +0.8m))(0.75 m) = 2.1 m²

  base area = lw = (0.8 m)(0.6 m) = 0.48 m²

The total area is then ...

  total area = half-cylinder area + lateral area + base area

  = 1.0362 m² +2.1 m² +0.48 m²

  = 3.6162 m²

__

The area for 1960 mailboxes will be 1960 times this area, or ...

  area for week's production = 1960 × 3.6162 m² = 7087.752 m²

It will take about 7088 square meters of aluminum to make these mailboxes.

5 0
3 years ago
Sam rides his bike at a rate of 15 miles per hour. How many feet per minute is this?
Triss [41]
Si tu prend un chien de 12k je crois que ta réponse va donner 15000
7 0
3 years ago
Graph the first six terms of a sequence where a1 = 2 and r = 4.
zavuch27 [327]
We are given with
a1 = 2
r = 4

These are components of a geometric series. The first term is 2 and the common ratio is 4. To get the first six terms, we use the formula:
an = a1 r^(n-1)
a1 = 2 (4)^(1-1) = 2
a2 = 2 (4)^(2-1) = 8
a3 = 2 (4)^(3-1) = 32
a4 = 2 (4)^(4-1) = 128
a5 = 2 (4)^(5-1) = 512
a6 = 2 (4)^(6-1) = 2048
8 0
3 years ago
Read 2 more answers
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