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3 years ago

14

My question is probably obvious but I don't know it. What is the z axis

1 answer:

Zigmanuir [339]3 years ago

8 0

Answer:

z-Axis. The axis in three-dimensional Cartesian coordinates which is usually oriented vertically. Cylindrical coordinates are defined such that the -axis is the axis about which the azimuth coordinate. is measured.

Step-by-step explanation:

You might be interested in

Neil is analyzing two linear functions, f(x) and g(x). Will they intersect?

LUCKY_DIMON [66]

No, the two lines do NOT intersect because they are parallel lines (see the attached image). Both lines have a slope of 2, or 2/1. Recall that slope = rise/run. So this means that we go up 2 and over to the right 1. Lines with the same slope but different y intercepts means that they are parallel. Parallel lines never cross.

In short, the final answer is choice D.

5 0

3 years ago

Which of the following statements is true? The value π is a rational number. The number 0 is a natural number. The number is an

AlexFokin [52]

Answer:

the number -5 is a real number

Step-by-step explanation:

real numbers are basically all numbers.... if you havent met complex numbers yet..

hopefuly this helped

:)

7 0

2 years ago

Read 2 more answers

What is the circumference of a circle that has the radius of 3cm

dexar [7]

Step-by-step explanation:

Circumference of a circle is 2piR

Here R is 3 cm

So C=2pi(3)

C=6pi cm

5 0

3 years ago

0.2% of 16<br><br> Pls show work.

sattari [20]

Answer:

0.512

Step-by-step explanation:

0.2%x16=0.032

0.032x16= 0.512

7 0

3 years ago

What is the sum of 20x^2-10x-30

ivann1987 [24]

Answer:

The sum of the roots is 0.5

Step-by-step explanation:

<u><em>The correct question is</em></u>

What is the sum of the roots of 20x^2-10x-30

we know that

In a quadratic equation of the form

$ax^{2} +bx+c=0$

The sum of the roots is equal to

$-\frac{b} {a}$

in this problem we have

$20x^{2} -10x-30=0$

so

$a=20\\b=-10\\c=-30$

substitute

$-\frac{(-10)} {20}=0.5$

<u><em>Verify</em></u>

Find the roots of the quadratic equation

The formula to solve a quadratic equation is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

$a=20\\b=-10\\c=-30$

substitute

$x=\frac{-(-10)\pm\sqrt{-10^{2}-4(20)(-30)}} {2(20)}$

$x=\frac{10\pm\sqrt{2,500}} {40}$

$x=\frac{10\pm50} {40}$

$x=\frac{10+50} {40}=1.5$

$x=\frac{10-50} {40}=-1$

The roots are x=-1 and x=1.5

The sum of the roots are

$-1+1.5=0.5$ ----> is ok

5 0

3 years ago