Question

What is the equation of a line that passes through the points (2, -2) and (8, 4)?

Answer 1

Answer:

x-y-4=0

Step-by-step explanation:

x1=2

X2=8

y1=-2

y2=4

slope=y2-y1/x2-x1

=4-(-2)/8-2

=6/6

=1

eqn of line is given by:

y-y1=m(x-x1)

y-(-2)=1(x-2)

y+2=x-2

x-y-4=0