Answer:
1
Step-by-step explanation:
The constant term in a perfect square trinomial with leading coefficient 1 is the square of half the coefficient of the linear term.
(2/2)² = 1
The missing constant term is 1.
Which transformations can be used to map a triangle with vertices A(2, 2), B(4, 1), C(4, 5) to A’(–2, –2), B’(–1, –4), C’(–5, –4
jek_recluse [69]
Notice that every pair of point (x, y) in the original picture, has become (-y, -x) in the transformed figure.
Let ABC be first transformed onto A"B"C" by a 90° clockwise rotation.
Notice that B(4, 1) is mapped onto B''(1, -4). So the rule mapping ABC to A"B"C" is (x, y)→(y, -x)
so we are very close to (-y, -x).
The transformation that maps (y, -x) to (-y, -x) is a reflection with respect to the y-axis. Notice that the 2. coordinate is same, but the first coordinates are opposite.
ANSWER:
"<span>a 90 clockwise rotation about the origin and a reflection over the y-axis</span>"
135, 140, 145, 150, 155, 160, 165, 170, 175. The last digit is either a 0 or a 5. I hope this helped. :) Brainlest answer?
Answer: The area of the enlargement is 315cm.
Step-by-step explanation:
If the picture has 35cm as the area and it has a length of 7cm then we can find the width by dividing the area by the length.
w= 35/7
w = 5
So in this care the width of the picture in 5cm.
Now is saying that the picture's length has been enlarge or been dilated to 21 cm. To get from 7cm to 21cm you will have to multiply by 3.
In this situation, we will have to multiply the original picture's width by 3 to find it enlargement.
w= 5*3 = 15
The width is 15cm and the length is 21cm so multiply them to find the area.
A = 15 * 21
A = 315cm
Both solutions:
x = -1, -7/3