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Ivenika [448]
3 years ago
6

Is this correct? I will give brainliest to the correct answer

Mathematics
2 answers:
tankabanditka [31]3 years ago
5 0
Oh yeah, now give me branliest.
Readme [11.4K]3 years ago
5 0

Answer:

so what you need to do here to check your work is to find 14 and 20 squared (which are 196 and 400) now your equation is 196 + 400 = c^2. now, you combine the like terms to make 596 = c^2. all you have to do now is find the square root of 596 (which is 24.4 when rounded to the nearest tenth). so yes, you are correct.

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Exercise 6.13 presents the results of a poll evaluating support for the health care public option in 2009, reporting that 52% of
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Answer:

A sample size of 6755 or higher would be appropriate.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error M is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

52% of Independents in the sample opposed the public option.

This means that p = 0.52

If we wanted to estimate this number to within 1% with 90% confidence, what would be an appropriate sample size?

Sample size of size n or higher when M = 0.01. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.01 = 1.645\sqrt{\frac{0.52*0.48}{n}}

0.01\sqrt{n} = 0.8218

\sqrt{n} = \frac{0.8218}{0.01}

\sqrt{n} = 82.18

\sqrt{n}^{2} = (82.18)^{2}

n = 6754.2

A sample size of 6755 or higher would be appropriate.

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Two angles are complementary. one angle is 63.5 degrees. what is the other angle?
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