All categories

3 years ago

Find the midpoint of the segment with the given endpoints.

2 answers:

7 0

To solve for the midpoint of the segment we use the equation that is given as:

(x1 + x2 / 2) , (y1 + y2 / 2)

For the points given,

(x1 + x2 / 2) , (y1 + y2 / 2)
(3+ 2 / 2) , (-5 + 9 / 2)
(5/2 , 2) or (2.5 , 2)

Hope this answers the question. Have a nice day. Feel free to ask more questions.

yanalaym [24]3 years ago

4 0

Answer:

The correct option is C.

Step-by-step explanation:

Given information: End point of a line segment are A(3, –5) and C(2, 9).

We to find the midpoint of line segment AC.

If the end point of a segment are $(x_1,y_1)$ and $(x_2,y_2)$ , then the midpoint of that segment is

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

$Midpoint=(\frac{3+2}{2},\frac{-5+9}{2})$

On simplification, we get

$Midpoint=(\frac{5}{2},\frac{4}{2})$

$Midpoint=(2.5,2)$

The midpoint of given segment is (2.5,2). Therefore the correct option is 3.

You might be interested in

Which of these statements is true for f(x)=(1/10)^x

lana66690 [7]

Step-by-step explanation:

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

Analyzing option A)

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

Putting $x = 1$ in the function

$f\left(1\right)=\:\left(\frac{1}{10}\right)^1$

$f\left(1\right)=\:\left\frac{1}{10}\right$

So, it is TRUE that when $x = 1$ then the out put will be $f\left(1\right)=\:\left\frac{1}{10}\right$

Therefore, the statement that '' The graph contains $\left(1,\:\frac{1}{10}\right)$ '' is TRUE.

Analyzing option B)

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

The range of the function is the set of values of the dependent variable for which a function is defined.

$\mathrm{The\:range\:of\:an\:exponential\:function\:of\:the\:form}\:c\cdot \:n^{ax+b}+k\:\mathrm{is}\:\:f\left(x\right)>k$

$k=0$

$f\left(x\right)>0$

Thus,

$\mathrm{Range\:of\:}\left(\frac{1}{10}\right)^x:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)>0\:\\ \:\mathrm{Interval\:Notation:}&\:\left(0,\:\infty \:\right)\end{bmatrix}$

Therefore, the statement that ''The range of $f(x)$ is $y > \frac{1}{10}$ " is FALSE

Analyzing option C)

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

The domain of the function is the set of input values which the function is real and defined.

As the function has no undefined points nor domain constraints.

So, the domain is $-\infty \:$

Thus,

$\mathrm{Domain\:of\:}\:\left(\frac{1}{10}\right)^x\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

Therefore, the statement that ''The domain of $f(x)$ is $x>0$ '' is FALSE.

Analyzing option D)

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

As the base of the exponential function is less then 1.

i.e. 0 < b < 1

Thus, the function is decreasing

Also check the graph of the function below, which shows that the function is decreasing.

Therefore, the statement '' It is always increasing '' is FALSE.

Keywords: function, exponential function, increasing function, decreasing function, domain, range

Learn more about exponential function from brainly.com/question/13657083

#learnwithBrainly

3 0

4 years ago

Read 2 more answers

Pls help me, this is past due and every day it’s pasted due I get points deducted:( (I have an F in math)

Sunny_sXe [5.5K]

Answer:

Part A: 3 3/4 Part B: 5 1/4

Step-by-step explanation:

Part A: 3/4x5=3 3/4

Part B: 3 3/4 +1 2/4=5 1/4

8 0

3 years ago

PLEASE HELP ME !! GEOMETRY REFLECTIONS!! PLEASE EXPLAIN

mr_godi [17]

The reflected image 1 is the image of reflected in the mirror line y=0 and the reflected image under y =2 is reflected and the mirror line y is equal to 2 hence the answer is (5,2)...

the number that belongs to the green box is 5

3 0

4 years ago

Which equation can be used to calculate the surface area of the triangular prism net show below?

deff fn [24]

Answer:

the answer is a

Step-by-step explanation:

4 0

3 years ago

Given the equation (x-a)^2(x-2)=x^3+bx^2+12x-72 find a and b

ivann1987 [24]

Isolate the variable by dividing each side by factors that don't contain the variable.

a=- \frac{ x^{2}- \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2} ,- \frac{ x^{2}+ \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2}

Solve for b by simplifying both sides of the equation then isolating the variable.

b= \frac{12}{x}+ \frac{72}{ x^{2} }-2+2a- \frac{4a}{x}+ \frac{ a^{2} }{x}- \frac{2a^{z} }{ x^{2} }

Hopefully i helped ^.^ Mark brainly if possible. Lol once again i saw the same question so why not answer it again!

3 0

3 years ago