Answer:
A
Step-by-step explanation: You are correct!
The answer is: 117m²
The explanation is shown below:
1. You have the following information given in the problem:
- The triangle has an area of 13 m².
- The dimensions of the triangle are increased by a scale factor of 3.
2. Therefore, to solve the exercise you must multiply the area by
, as following:

Answer:
find the same x-value and the same y-value that satisfies both ... 1 2 3. + 4 5 6. 5 7 9 ... + (4x – 2y + 9 = 0).
Step-by-step explanation:
The first to find the length of each side, we have to find the value of x :







<span>
<u>Solution First side :</u></span>

<span>
<u>Solution Second Side :</u></span>

<span>
<u>Solution Third Side :</u></span>