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exis [7]
3 years ago
13

Determine whether the sequence converges or diverges. If it converges, give the limit.

Mathematics
2 answers:
Sveta_85 [38]3 years ago
7 0
The sequence is a geometric sequence with a common ratio of 2. since the common ratio is greater than 1, the sequence diverges.
andre [41]3 years ago
3 0

Answer:

Diverges

Step-by-step explanation:

The given sequence is:

11, 22, 44, 88,.....

Now, a_{1}=11=2^0{\times}11,

a_{2}=22=2^1{\times}11,

a_{3}=44=2^2{\times}11,

a_{4}=88=2^3{\times}11

Thus,the nth term will be: a_{n}=2^{n-1}{\times}11.

Now, as \lim_{n \to \infty} a_n, then

\lim_{n \to \infty} a_n=2^{n-1}{\times}11=+{\infty}

Since, as n{\rightarrow}{\infty}, a_{n}{\rightarrow}+{\infty}, thus the given sequence diverges.

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