Answer:
-2(x^2+15)
Step-by-step explanation:
f(x) = −2(x − 4)^2 + 2.
Expanding (x-4)^2
(x-4)(x+4)
x(x+4)-4(x+4)
x^2+4x-4x-16
x^2-16
F(x) = -2(x^2-16)+2
-2x^2-32+2
-2x^2-30
-2(x^2+15)
Answer:
x+3y-6=0
Step-by-step explanation:
given eqn is y=3x-2 which is 3x-y-2=0
the eqn of line perpendicular to given eqn is -x+3y+k=0
it passes through (6,4)
-6+3*4+k=0
or,. -6+12+k=0
or, k= -6
therefore, the eqn of line perpendicular to given eqn is x+3y-6=0
The inputs are 1 and -1 when the output is 2.
Step-by-step explanation:
The given function is
f(x) = 10 x²
Then we set y = f (x)
y = 10 x²
By dividing each side by 10 we get
x² = y/10
Then we solve for x
x = ±
Now we have to find the input(s) when the output is 10
x = ±
x = ± 1
Hence, the inputs are 1 and -1 when the output is 2.
The final solution is x =1 and x = -1.