Answer:
Hannah's dog is 52 pounds
Step-by-step explanation:
Ava's = 20.8
Hannah's = 20.8 x 2.5
20.8 x 2.5 = 52
52 pounds
Hope this helps!
Answer:
Approximatley 5.8 units.
Step-by-step explanation:
We are given two angles, ∠S and ∠T, and the side opposite to ∠T. We need to find the unknown side opposite to ∠S. Therefore, we can use the Law of Sines. The Law of Sines states that:
Replacing them with the respective variables, we have:
Plug in what we know. 20° for ∠S, 17° for ∠T, and 5 for <em>t</em>. Ignore the third term:
Solve for <em>s</em>, the unknown side. Cross multiply:
<h2>(x + 4) (x + 4)</h2>
Step-by-step explanation:
= x² + 8x + 16
= x² + 4x + 4x + 16
= x (x + 4) + 4 (x + 4)
= (x + 4) (x + 4)
<h2>follow me</h2>
Answer:
Option D. -0.901
Step-by-step explanation:
we know that
<u>The correlation coefficient</u> r measures the strength and direction of a linear relationship between two variables. The value of r is always between +1 and –1
Using a Excel tool (Correl function)
The value of coefficient r is -0.9006876
Round to three decimal places
r=-0.901
see the table attached
Relations are subsets of products A×BA×B where AA is the domain and BB the codomain of the relation.
<span>A function <span>ff</span> is a relation with a special property: for each <span><span>a∈A</span><span>a∈A</span></span> there is a unique <span><span>b∈B</span><span>b∈B</span></span> s.t. <span><span>⟨a,b⟩∈f</span><span>⟨a,b⟩∈f</span></span>.This unique <span>bb</span> is denoted as <span><span>f(a)</span><span>f(a)</span></span> and the 'range' of function <span>ff</span> is the set <span><span>{f(a)∣a∈A}⊆B</span><span>{f(a)∣a∈A}⊆B</span></span>.You could also use the notation <span><span>{b∈B∣∃a∈A<span>[<span>⟨a,b⟩∈f</span>]</span>}</span><span>{b∈B∣∃a∈A<span>[<span>⟨a,b⟩∈f</span>]</span>}</span></span>Applying that on a relation <span>RR</span> it becomes <span><span>{b∈B∣∃a∈A<span>[<span>⟨a,b⟩∈R</span>]</span>}</span><span>{b∈B∣∃a∈A<span>[<span>⟨a,b⟩∈R</span>]</span>}</span></span>That set can be labeled as the range of relation <span>RR</span>.</span>