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lara31 [8.8K]
3 years ago
6

Help me solve this please 33+15w=3w-w+4w

Mathematics
1 answer:
hichkok12 [17]3 years ago
8 0

Answer:

33+15w=3w-w+4w

33+15w - 15w=3w-w+4w -15w

33 = 2w + 4w -15w

33 = 6w -15w

33 = -9w

33/9 = -9/9w

3.66 = w

Step-by-step explanation:

33+15w=3w-w+4w

33+15w - 15w=3w-w+4w -15w

33 = 2w + 4w -15w

33 = 6w -15w

33 = -9w

33/9 = -9/9w

3.66 = w

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2 years ago
What is the inverse of the function
Evgesh-ka [11]

Answer:

A

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

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x³ = \frac{19}{y} ( take the cube root of both sides )

x = \sqrt[3]{\frac{19}{y} }

Change y back into terms of x, then

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3 years ago
A rectangle has a length of the fifth root of 16 inches and a width of 2 to the 1 over 5 power inches. Find the area of the rect
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Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
If 35.4067=3/p+5/q+4r+6/s+7t, then the value of 2p+4q+5r+7s+3t​
sweet [91]

Answer:

7004.7003

Step-by-step explanation:

We are given the following information in the question:

35.4067=\displaystyle\frac{3}{p}+\frac{5}{q}+4r+\frac{6}{s}+7t

We know that,

35.4067 = (3\times 10^1) + (5\times 10^0) + (4\times 10^{-1})+(0\times 10^{-2}) + (6\times 10^{-3}) + (7\times 10^{-4})

Comparing the two equations, we get:

\displaystyle\frac{1}{p} = 10^1\\\\p = 10^{-1}\\q = 10^0\\r = 10^{-1}\\s = 10^3\\t = 10^{-4}

We have to evaluate:

2p+4q+5r+7s+3t

Putting values, we get:

(2\times 10^{-1}) + (4\times 10^0) + (5\times 10^{-1}) + (7\times 10^3) + (3\times 10^{-4})\\=0.2 + 4 + 0.5 + 7000 + 0.0003\\=7004.7003

8 0
3 years ago
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