Answer: Probably Fee.
Step-by-step explanation:
The first choice can be any one of the 8 side dishes.
For each of these . . .
The 2nd choice can be any one of the remaining 7.
Total number of ways to pick 2 out of 8 = (8 x 7) = 56 ways .
BUT ...
That doesn't mean you can get 56 different sets of 2 side dishes.
For each different pair, there are 2 ways to choose them . . .
(first A then B), and (first B then A). Either way, you wind up with (A and B).
So yes, there are 56 different 'WAYS' to choose 2 out of 8.
But there are only 28 different possible results, and 2 'ways'
to get each result.
3+ - 1 I hole this helped
Let's call the number you thought of n. Then what the two steps you took can be written as an equation:
Subtract n to get all of your variables to one side:
At this point, I recommend turning your mixed number into an improper fraction. It will make things easier later on:
Now divide both sides by 11 to get the value of n: