#1: The temperature would be 0 degrees F
#2: -7 degrees
#3: A
I hope this helps!
Answer:
angle C = 78
angle D = 108
Step-by-step explanation:
the measure of angle A is 102
To find the measure of angle C
let Angle C be x
102 + x = 180 (linear pair)
x = 180 -102
x = 78
angle C = 78
angle B = 78 (vertically opposite angles are equal)
angle D = 108 (vertically opposite angles are equal)
Answer:
t1= 5.35
Step-by-step explanation:
Projectile height formula should be
h= -1/2gt^2+v0t+h0
where
h= height, this question asking time when "ball hit the ground" so height is 0
t= time, we look for this variable
v0= initial velocity= 85 feet/s
h0= initial height = 6 feet
g= gravity, assumed 32 feet/s^2
The calculation will be:
h= -1/2gt^2+v0t+h0
0= -
32 t^2+85t+6
0= -16t^2+85t+6
16t^2 - 85t -6 =0
x= ![\frac{-b±\sqrt{ b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%C2%B1%5Csqrt%7B%20b%5E2-4ac%7D%7D%7B2a%7D)
t= ![\frac{(-(-85)±\sqrt{ -85^2-4(16)(-6)}}{2(16)}](https://tex.z-dn.net/?f=%5Cfrac%7B%28-%28-85%29%C2%B1%5Csqrt%7B%20-85%5E2-4%2816%29%28-6%29%7D%7D%7B2%2816%29%7D)
t= ![\frac{(-(-85)±\sqrt{7417}}{2(16)}](https://tex.z-dn.net/?f=%5Cfrac%7B%28-%28-85%29%C2%B1%5Csqrt%7B7417%7D%7D%7B2%2816%29%7D)
t= ![\frac{85±\sqrt{7417}}{32)}](https://tex.z-dn.net/?f=%5Cfrac%7B85%C2%B1%5Csqrt%7B7417%7D%7D%7B32%29%7D)
t= ![\frac{85±\ 86.12}{32}=](https://tex.z-dn.net/?f=%5Cfrac%7B85%C2%B1%5C%2086.12%7D%7B32%7D%3D)
t1= ![\frac{85+\ 86.12}{32}=](https://tex.z-dn.net/?f=%5Cfrac%7B85%2B%5C%2086.12%7D%7B32%7D%3D)
t1= 5.35
t2= ![\frac{85-\ 86.12}{32}=](https://tex.z-dn.net/?f=%5Cfrac%7B85-%5C%2086.12%7D%7B32%7D%3D)
t2= -0.035
The answer can't be minus, so its t1
Answer:
896+32=928in
Step-by-step explanation:
Answer:
15cm
Step-by-step explanation:
So first its 3:5 so take 25 and divide it by 5. This equals 5. Multiply it by 3 and you get 15cm. 15 is 3:5 of 25.