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Tcecarenko [31]
3 years ago
7

A forest fire is found at midnight. It covers 1200 acres then. It is spreading at a rate of f(t)= 5√t acres per hour. By how m

any acres will the fire grow between ​6:00 am and​ 10:00 am? Between ​6:00 am and​ 10:00 am the fire will grow by _________ acres.
Mathematics
1 answer:
Eddi Din [679]3 years ago
3 0

Answer:

49 acres

Step-by-step explanation:

Given that:

Initial coverage = 1200 at midnight

Spread rate = 5√t acres per hour

By how many acres will the fire grow between 6am and 10 am

Hours between (6 - 10) am = 6 hours

Take the integral of the rate function with upper limit = 6 and lower limit = 0

∫5√t dt at t = 6, t = 0

5∫√tdt = 5∫t^1/2 dt at t = 6, t = 0

5 (t^1/2 + 1 / 1/2 + 1) at t = 6, t = 0

5 ( t^3/2 / 3/2) at t = 6, t = 0

5 * 2/3 (t^3/2)

[10/3 *t^3/2] at t = 6, t = 0

(10/3 * 6^3/2) - (10/3 * 0^3/2)

(10/3 * 14.696938) - 0

48.989794

= 49 acres ( approximately)

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Give the values of a, b, and c needed to write the equation's general form.<br>1/4x^2+5=0
Firdavs [7]

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

   Hi my lil bunny!

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

Let's solve your equation step-by-step.

\frac{1}{4} x^2+5=0

For this equation: a=0.25, b=0, c=5

0.25x^2 + 0x + 5 = 0

Step 1: Use quadratic formula with a=0.25, b=0, c=5.

x = \frac{-b ± \sqrt{b^2 - 4ac} }{2a}

x = \frac{-(0) ± \sqrt{(0)^2 -4 (0.25) (5)  } }{2(0.25)}

x = \frac{0 ± \sqrt{-5} }{0.5}

Answer : No Real Solutions.

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●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

If this helped you, could you maybe give brainliest..?

Also Have a great day/night!

❀*May*❀

5 0
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