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VladimirAG [237]
3 years ago
6

Other question.........

Mathematics
2 answers:
astra-53 [7]3 years ago
6 0
That whole thing is a right angle, which is 90 degrees. put measure 1 and 2 and equal it to 90 and solve. 5x+x-12=90. combine like terms and solve for x. 6x-12=90. 6x=90+12. 6x= 102. x=17
evablogger [386]3 years ago
3 0

Answer:

m<1=85; m<2 =5

Step-by-step explanation:

5x + x - 12 = 90(right \: angle \: ) \\ 6x - 12 = 90 \\ 6x = 90 + 12 \\ 6x = 102 \\ x = 102 \div 6 \\ x = 17 \\ hence \: x = 17 \\ 5x = 5 \times 17 \\  = 85

x - 12 = 17 - 12 \\  = 5

to \: check \\  \\ 5x + x - 12 = 90 \\ 85 + 5 = 90 \\ hope \: it \: helps \\ pls \: mark \: it \: as \: brainliest...

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Julia is five years older than her sister Babs, and their ages add up to 31. How old is Babs?
Tresset [83]
<span>Julia is X+5

</span><span>x+x+5=31
</span>
Now we just solve the equation 

2x=31-5
x=26/2
x=13 years old (Babs' age)

and we know that julia is 5 years older this gives us the conclusion that. 

13+18=31
4 0
3 years ago
Read 2 more answers
1. Mitchell got a job at Owens that pays $38,173 a year thanks to the help of an employment agency. The
Akimi4 [234]

Answer:

38174:54*3*0.40

Step-by-step explanation:

1. calculate how much per week by

38174:54

2. than in 3 weeks

38174:54*3

3. than 40 percent of that

x*0.40

7 0
3 years ago
Frank is making a pennant in the shape of a triangle for his senior class photo. He wants the base length of this triangle to be
Sav [38]

Answer:

Height should be ≤ 9 inches.

Step-by-step explanation:

Given:

Frank is making a pennant in the shape of a triangle for his senior class photo.

Base of triangle = 6 in

Area of triangle ≤ 27 in^2

Let height of the triangle be h

Now we now that,

Area of triangle = \frac{1}{2}\times base \times height

\frac{1}{2}\times 6 \times h \leq 27\\\\3h\leq 27\\\\h\leq \frac{27}{3}\\\\h\leq 9 \ in.

Hence the height of the triangle must be at most or ≤ 9 inches.

5 0
3 years ago
What is the midpoint of (-2,3) and (10,3) *simple answer please
Allushta [10]

The "midpoint formula" is the same as the "average formula:"

x-coordinate of the midpoint = average of -2 and 10:

= (-2 + 10) / 2 = 4


y-coordinate of the midpoint = average of 3 and 3:

= (3+3) / 2 = 3

Thus, the midpoint of the given line segment is (4,3).


5 0
3 years ago
Test scores of the student in a school are normally distributed mean 85 standard deviation 3 points. What's the probability that
Mrrafil [7]

Answer:

The probability that a random selected student score is greater than 76 is \\ P(x>76) = 0.99865.

Step-by-step explanation:

The Normally distributed data are described by the normal distribution. This distribution is determined by two <em>parameters</em>, the <em>population mean</em> \\ \mu and the <em>population standard deviation</em> \\ \sigma.

To determine probabilities for the normal distribution, we can use <em>the standard normal distribution</em>, whose parameters' values are \\ \mu = 0 and \\ \sigma = 1. However, we need to "transform" the raw score, in this case <em>x</em> = 76, to a z-score. To achieve this we use the next formula:

\\ z = \frac{x - \mu}{\sigma} [1]

And for the latter, we have all the required information to obtain <em>z</em>. With this, we obtain a value that represent the distance from the population mean in standard deviations units.

<h3>The probability that a randomly selected student score is greater than 76</h3>

To obtain this probability, we can proceed as follows:

First: obtain the z-score for the raw score x = 76.

We know that:

\\ \mu = 85

\\ \sigma = 3

\\ x = 76

From equation [1], we have:

\\ z = \frac{76 - 85}{3}

Then

\\ z = \frac{-9}{3}

\\ z = -3

Second: Interpretation of the previous result.

In this case, the value is <em>three</em> (3) <em>standard deviations</em> <em>below</em> the population mean. In other words, the standard value for x = 76 is z = -3. So, we need to find P(x>76) or P(x>-3).

With this value of \\ z = -3, we can obtain this probability consulting <em>the cumulative standard normal distribution, </em>available in any Statistics book or on the internet.

Third: Determination of the probability P(x>76) or P(x>-3).

Most of the time, the values for the <em>cumulative standard normal distribution</em> are for positive values of z. Fortunately, since the normal distributions are <em>symmetrical</em>, we can find the probability of a negative z having into account that (for this case):

\\ P(z>-3) = 1 - P(z>3) = P(z

Then

Consulting a <em>cumulative standard normal table</em>, we have that the cumulative probability for a value below than three (3) standard deviations is:

\\ P(z

Thus, "the probability that a random selected student score is greater than 76" for this case (that is, \\ \mu = 85 and \\ \sigma = 3) is \\ P(x>76) = P(z>-3) = P(z.

As a conclusion, more than 99.865% of the values of this distribution are above (greater than) x = 76.

<em>We can see below a graph showing this probability.</em>

As a complement note, we can also say that:

\\ P(z3)

\\ P(z3)

Which is the case for the probability below z = -3 [P(z<-3)], a very low probability (and a very small area at the left of the distribution).

5 0
3 years ago
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