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2 years ago

Can someone help me with this please?

Mathematics

1 answer:

Daniel [21]2 years ago

5 0

Answer:

Classify by angles: <u>Equiangular</u>

Classify by sides: <u>Equilateral</u>

Step-by-step explanation:

An equiangular triangle has angles that all measure 60 degrees. An equilateral triangle is a triangle that has sides will all of the same lengths. This triangle meets both of these requirements.

Hope it helps!

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Write the equations of three distinct lines that have the same y-intercept,-1.

guajiro [1.7K]

Three possible answers are:
y = 2x-1
y = 5x-1
y = -3x-1

All of them have the same y intercept of -1. The slopes are the only thing that differ.

Any linear equation can be written in the form y = mx+b where
m = slope
b = y intercept

7 0

3 years ago

Write the equation of the line of best fit using the slope-intercept formula $y = mx + b$. Show all your work, including the poi

Dennis_Churaev [7]

Answer:

$y=\frac{5}{7}x+\frac{135}{7}$

Step-by-step explanation:

You only need two points on a line to find the equation for that line.

We are going to use 2 points that cross that line or at least come close to. You don't have to use the green points... just any point on the line will work. You might have to approximate a little.

I see ~(67.5,67.5) and ~(64,65).

Now once you have your points, we need to find the slope.

You may use $\frac{y_2-y_1}{x_2-x_1}$ where $(x_1,y_1) \text{ and } (x_2,y_2)$ are points on the line.

Or you can line up the points vertically and subtract then put 2nd difference over 1st difference.

Like this:

( 64 , 65 )

-( 67.5, 67.5 )

--------------------

-3.5 -2.5

So the slope is -2.5/-3.5=2.5/3.5=25/35=5/7.

Now use point-slope form to find the equation:

$y-y_1=m(x-x_1)$ where $m$ is the slope and $(x_1,y_1)$ is a point on the line.

$y-65=\frac{5}{7}(x-64)$

Distribute:

$y-65=\frac{5}{7}x-\frac{5}{7}\cdot 64$

Simplify:

$y-65=\frac{5}{7}x-\frac{320}{7}$

Add 65 on both sides:

$y=\frac{5}{7}x-\frac{320}{7}+65$

Simplify:

$y=\frac{5}{7}x+\frac{135}{7}$

6 0

3 years ago

Determine 2nd term and rth term of a.p.whose 6 th term is 12 and 8 th term is 22

Vanyuwa [196]

Answer:

see explanation

Step-by-step explanation:

The n th term of an arithmetic progression is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given $a_{6}$ = 12 and $a_{8}$ = 22, then

a₁ + 5d = 12 → (1)

a₁ + 7d = 22 → (2)

Subtract (1) from (2) term by term to eliminate a₁

2d = 10 ( divide both sides by 2 )

d = 5

Substitute d = 5 into (1) to find a₁

a₁ + 5(5) = 12

a₁ + 25 = 12 ( subtract 25 from both sides )

a₁ = - 13

Thus

$a_{2}$ = - 13 + 5 = - 8

$a_{n}$ = - 13 + 5(n - 1) = - 13 + 5n - 5 = 5n - 18 ← n th term

8 0

3 years ago

What is the solution of the inequality x/3 > 1?

Alika [10]

If you would like to know what is the solution of the inequality x/3 > 1, you can calculate this using the following step:

x/3 > 1 /*3
x > 1 * 3
x > 3

The correct result would be x > 3.

6 0

3 years ago

Simplify the rational expression. State any restrictions on the variable. t^2-4t-32/t-8

Leno4ka [110]

1. Factor the expression $t^2-4t-32:$