The sum of x and 3/5 is 5/7

a camera sells for $100. this is $10 less than twice the price of the camera last year. what was the price of the camera last ye

Lesechka [4]

Answer:

55?

Step-by-step explanation:

110 would be the last year for two and then divide by two

8 0

3 years ago

The following data points are the yearly salaries (in thousands of dollars) of the 4 high school cheerleading

GarryVolchara [31]

Answer:

6

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A test requires that you answer either part A or part B. Part A consists of 7 true-false questions, and part B consists of 5 mul

jeka94

Answer: 3253

Step-by-step explanation:

Given : A test requires that you answer either part A or part B.

Part A consists of 7 true-false questions.

i.e. there are 2 choices to answer each question.

Now, the number of ways to answer Part A : $2^7=128$ (1)

Part B consists of 5 multiple-choice questions with one correct answer out of five.

i.e. there are 5 choices to answer each question.

Now, the number of ways to answer Part B : $5^5=3125$ (2)

Now, the number of different ways to completed answer sheets are possible= $128+3125=3253$ [Add (1) and (2) ]

5 0

3 years ago

What is the value of the expression below when x equals 4? 13 + 15x

antoniya [11.8K]

Answer:

73

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth

MAXImum [283]

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

$\twoheadrightarrow \quad\sf{ Length =2(Width)-5}$

$\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}$

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

$\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\$

l denotes length
b denotes breadth

$\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\$

$\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\$

$\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\$

$\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\$

$\\ \twoheadrightarrow \quad\sf{60= 6b} \\$

$\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\$

$\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\$

Now, finding the length. According to the question,

$\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}$

$\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}$

$\twoheadrightarrow \quad\sf{ \ell=20-5\; m}$

$\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\$

Therefore, length and breadth of the rectangle is 15 m and 10 m. 

7 0

3 years ago