The sum of x and 3/5 is 5/7

A candy jar has 24 candies. One-third of the candies are chocolates. Of the leftover candies, half are gummy bears and the other

Dennis_Churaev [7]

8 skittles hope this helps

8 0

2 years ago

Chapter 6, Section 1-D, Exercise 009 Is a Normal Distribution Appropriate? In each case below, is the sample size large enough s

Xelga [282]

Answer:

Step-by-step explanation:

Complete Question:

Chapter 6, Section 1-D, Exercise 009 Is a Normal Distribution Appropriate? In each case below, is the sample size large enough so that the sample proportions follow a normal distribution?

a) n=600 p=0.2

b) n=20, p=0.4

if np=10 and npq=10 then the data follows normal distribution

a) np= 120,

q= 1-0.2= 0.8

npq= 600 ×0.2×0.4 = 48

Normal distribution is appropriate and sample size is large enough

b) np= 8

q= 1-0.4= 0.6

npq= 20 × 0.4×0.6= 4.8

sample size is not large enough so normal distribution is not appropriate.

4 0

3 years ago

Which are the solutions of x^2 = –11x + 4?

strojnjashka [21]

This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get

$x^2 + 11x - 4 = 0$

i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:

$x_{1,2} = \frac{-b\pm\sqrt{b^2-4ac}}{2}$

where $x_{1,2}$ is a compact way to indicate both solutions $x_1$ and $x_2$ , while $a,b,c$ are the coefficients of the quadratic equation, i.e. we consider the polynomial $ax^2+bx+c$ .

So, in your case, we have $a=1,\ \ b=11,\ \ c=-4$

Plug those values into the formula to get

$x_{1,2} = \frac{-11\pm\sqrt{121+16}}{2} = \frac{-11\pm\sqrt{137}}{2}$

So, the two solutions are

$x_1 = \frac{-11+\sqrt{137}}{2}$

$x_2 = \frac{-11-\sqrt{137}}{2}$