Given: <span>y = x^2 + 6x - 5. Then a = 1, b = 6 and c = -5.
The x-coord. of the vertex is given by x = -b / (2a), which here is x = -6 / (2*1) = -3.
Use the given formula </span><span>y = x^2 + 6x - 5 to find the value of y when x = -3:
y = (-3)^2 + 6(-3) - 5 = 9 - 18 - 5 = -14
Then the vertex is (-3, -14).</span>
Since we will be completing the square we need to isolate the x
y-5 = 2x^2 -4x
now we the coefficient of the x^2 to equal 1 so we take 2 as common factor
y-5 = 2(x^2 -2x)
now we'll make it perfect square by adding 2 to both sides
y-5+2=2(x^2-2x+1)
now simplify and convert the right side to squared expression
y-3 = 2(x-1)^2
now isolate the y
y = 2(x-1)^2 +3 that's it
Answer:
<h2>I think that is a FORMULA.</h2>
it can't be solved if we don't know the values of atleast one of the x and y.
Hope this helps.
Good luck ✅.
