I'll answer and explain, its pretty much the last question. Easy way to put it,
1 and 4 are diagonal from each other so they are the same number.
1 and 4 = 120
2 and 3 are diagonal so they both = 60
Same thing for the bottom
1=120
2=60
3=60
4=120
5=120
6=60
7=60
8=120
What is asked here is that you isolate y so that the equation takes the form of y = ..., where ... will be something that contains a, b and c but not y. So how do we get there? By applying some standard permutations to equations like so:
aby - b = c
First, we bring the -b term to the right hand side by adding b left and right:
aby -b+b = c+b
The -b and +b cancel out, so we get:
aby = c + b
Then, we divide left and right hand side by ab:
aby/ab = (c+b)/ab
Again, the ab/ab on the left cancels out (it is 1), so we get:
y = (c+b)/ab
And we're done!
So you have to know that it is allowed to add or subtract something (anything) to/from the left and right hand side of an equation. Likewise, you have to know that it is allowed to multiply or divide by something, as long as it isn't 0.
Answer:
-10y - 11x
Step-by-step explanation:
First you need to distribute -7 through the parentheses.
-7y - 14x - 3y + 3x
then you need to collect the like terms (terms with the same variable)
-10y - 11x
If it is perpendicular to the line 14x-7y=4, then we know our line has the opposite and inverse slope of that line. Solving for y of the first line, we get y=2x-(4/7). All we care about is the coefficient of the x term, because that will give us our slope. The slope of the first line is 2, so the slope of out line is the opposite and inverse of that slope, which -(1/2).
Plugging into our slope- point formula, where y1=(-9), x1=2, and m=(-1/2), then:
y-(-9)=(-1/2)(x-2)
y+9=(-1/2)x+1
y=(-1/2)x-8
Hope this helps!
