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Illusion [34]
3 years ago
8

5. Put the following fractions in order from smallest to largest: 1/4, 2/3, 4/7, 1/2

Mathematics
1 answer:
AVprozaik [17]3 years ago
7 0

Answer:

4/7, 1/4,1/2, 2/3

Step-by-step explanation:

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Drag the expressions into the boxes to correctly complete the table.
lora16 [44]

Answer:

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

Step-by-step explanation:

The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form ax^n.

Here:

n = non-negative integer

a = is a real number (also the the coefficient of the term).

Lets check whether the Algebraic Expression are polynomials or not.

Given the expression

x^4+\frac{5}{x^3}-\sqrt{x}+8

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains \sqrt{x}, so it is not a polynomial.

Also it contains the term \frac{5}{x^3} which can be written as 5x^{-3}, meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression x^4+\frac{5}{x^3}-\sqrt{x}+8 is not a polynomial.

Given the expression

-x^5+7x-\frac{1}{2}x^2+9

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.

Given the expression

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!

Given the expression

\left|x\right|^2+4\sqrt{x}-2

is not a polynomial because algebraic expression contains a radical in it.

Given the expression

x^3-4x-3

a polynomial with a degree 3. As it does not violate any condition as mentioned above.

Given the expression

\frac{4}{x^2-4x+3}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

3 0
3 years ago
Draw and label an example of each type of quadrilateral:trapezoid parallelogram rhombus rectangle and square pls help meeeee I n
Elden [556K]
How can I send the pic?

4 0
3 years ago
.......................................................................
Maslowich
Is this a glitch or I don’t see a question? I only see dots “……”
4 0
2 years ago
13. The perimeter P (in yards) of a soccer field is represented by the formula P = 24 + 2w,
rjkz [21]

Answer:

w = \frac{1}{2}(P - 24)

w = 153\ yards

Step-by-step explanation:

Given

P = 24 + 2w

Require

Solving (a):

P = 24 + 2w

Subtract 24 from both sides

P-24 = 24-24 + 2w

P-24 = 2w

Divide both sides by 2

\frac{1}{2}(P - 24) = \frac{2w}{2}

\frac{1}{2}(P - 24) = w

w = \frac{1}{2}(P - 24)

Solving (b):

Substitute 330 for P un the expression in (1)

w = \frac{1}{2}(330 - 24)

Evaluate the bracket

w = \frac{1}{2}(306)

w = 153\ yards

<em>Question c; seem irrelevant</em>

7 0
3 years ago
Find the equation (in terms of x ) of the line through the points (-1,4) and (2,-5)
marishachu [46]

Answer:

( 1 , -3 ) for every +1 on the x line you go -3 on the y I hope this is what you need

6 0
3 years ago
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