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zepelin [54]
3 years ago
6

Hey can i please get help!

Mathematics
2 answers:
Maslowich3 years ago
8 0

Answer:

Can you maybe add the pic for the options like the other have said?

Step-by-step explanation:

MaRussiya [10]3 years ago
7 0
The answer is uniforms
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A store sells a package of 25 trading cards for​ $5.25. Use pencil and paper. Explain how you can tell that the unit price per c
zzz [600]

Answer:

21 cent per card

Step-by-step explanation:

5.25 / 25 = .21

because 25 can be divided into the first 2 numbers

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2 years ago
Fill in the table of values for the function (fx)=3(2)^x
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Step-by-step explanation:

-2 = 0.75

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3 years ago
Xavier can work no more than 40 hours in a week. He has already worked 24 hours this week. What is the maximum number of 8-hour
ozzi
16 i think idk though
6 0
3 years ago
Read 2 more answers
Divide the following fractions and reduce to lowest terms 2/3 divided by 4/5
pshichka [43]
Well to divide 2 fraction you first have to find a least common number between the 2 bottom numbers in the fractions, we know automaticall that 15 fits in both the 3 and the 5. now u have to find out what to multiply by each number to get 15, for example what number do you multiply by 3 to get 15?? well it will be 5, so go ahead and multiply it by the fraction (note that what you do  in the bottom you have to do in the top) this will give you 10/15, because I multiplied the top and bottom number by 5... lets try the other one what number do you multiply by 5 to get 15?? well it will be 3 so go ahead and multiply that to get 12/15.. now add the top numbers (note that the bottoms always stay the same, you never add or subtract them) when you do you will get 22/15, now you have to see if you can simplify it any further in this case you can't so your final answer is 22/15

Hope this helps
5 0
3 years ago
How to solve this linear equation step by step please
mote1985 [20]
\bf \cfrac{3}{c^2-4c}-\cfrac{9}{2c^2+3c}=\cfrac{2}{2c^2-5c-12}\\\\\\ 
\begin{cases}
c^2-4c=&c(c-4)\\
2c^2+3c=&c(2c+3)\\\\
2c^2-5c-12=
&(2c+3)(c-4)
\end{cases}\\\\
-------------------------------\\\\
\textit{therefore, our LCD for the \underline{left-side} will have to be }\underline{c(c-4)(2c+3)}\\\\
-------------------------------\\\\

\bf \cfrac{3}{c(c-4)}-\cfrac{9}{c(2c+3)}=\cfrac{2}{(2c+3)(c-4)}
\\\\\\
\cfrac{3(2c+3)-9(c-4)}{c(c-4)(2c+3)}=\cfrac{2}{(2c+3)(c-4)}
\\\\\\
\cfrac{6c+9-(9c-36)}{c(c-4)(2c+3)}=\cfrac{2}{(2c+3)(c-4)}
\\\\\\
\cfrac{6c+9-9c+36}{1}=\cfrac{2[c(c-4)(2c+3)]}{(2c+3)(c-4)}
\\\\\\
-3c+45=2c\implies 45=5c\implies \cfrac{45}{5}=c\implies 9=c
7 0
3 years ago
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