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3 years ago

14

Sid wrote 541,309 on his paper.Using numbers and words, explain how the number would change if he exchanged the digit in the hun

dred thousands and tens place

1 answer:

olga nikolaevna [1]3 years ago

3 0

If he switched those around, you new number will be; 41,359

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I need help again if I don't get this right then I'll have to do the lesson all over again and i'm already 10 lessons behind!

zhuklara [117]

Answer:

1/27 in ^3

Step-by-step explanation:

where length - 1/3 inches

width - 1/3 inches

height - 1/3 inches

the formula to find volume is as follows

volume =

numerators should be multiplied by numerators and denominators by denominators

volume =

volume of the cube is 1/27 in.³

7 0

3 years ago

Read 2 more answers

Write an addition problem that has 9/10 as the sum

kicyunya [14]

There are a number of different problems that you could do that will give you an outcome of 9/10
For example, 1/2 and 2/5 add up to 9/10.
3/10 and 6/10 also add up to 9/10.

Find the sum of 7/10 and 1/5
Find the sum of 7/20 and 11/20
Find the sum of 1/2 and 3/10 and 1/10
Find the sum of 1/5 and 2/5 and 3/10

Hope this helps :)

3 0

2 years ago

If x = y + z and x + y =6 and x = 10, then z = _____?

7nadin3 [17]

X+y=6
x=10

10+y=6
y=-4

10=-4+z
-4+z=10
z=10+4
z=14

So the correct answer is 14

4 0

3 years ago

Read 2 more answers

Find a polynomial with a degree of 3, and the zeros 1,7, & -4 with no other zeros.

jarptica [38.1K]

Answer:

$f(x)=(x+4)(x-7)(x-1)$

Step-by-step explanation:

zeroes are when you plug in that x value and get y=0

therefore if you set x = that number and solve for 0 you get a "function"

multiplying these together will yield the complete 3rd degree polynomial

x = 1

x-1=0

x=7

x-7=0

x=-4

x+4=0

$f(x)=(x+4)(x-7)(x-1)$

If needed you could expand but I'm too lazy

5 0

2 years ago

PLEASE HELP ASAP! I don’t recall how to do this!

MakcuM [25]

Answer:

Step-by-step explanation:

For a. we start by dividing both sides by 200:

$(1.05)^x=1.885$

In order to solve for x, we have to get it out from its position of an exponent. Do that by taking the natural log of both sides:

$ln(1.05)^x=ln(1.885)$

Applying the power rule for logs lets us now bring down the x in front of the ln:

x * ln(1.05) = ln(1.885)

Now we can divide both sides by ln(1.05) to solve for x:

$x=\frac{ln(1.885)}{ln(1.05)}$

Do this on your calculator to find that

x = 12.99294297

For b. we will first apply the rule for "undoing" the addition of logs by multipllying:

$ln(x*x^2)=5$

Simplifying gives you

$ln(x^3)=5$

Applying the power rule allows us to bring down the 3 in front of the ln:

3 * ln(x) = 5

Now we can divide both sides by 3 to get

$ln(x)=\frac{5}{3}$

Take the inverse ln by raising each side to e:

$e^{ln(x)}=e^{\frac{5}{3}}$

The "e" and the ln on the left undo each other, leaving you with just x; and raising e to the power or 5/3 gives you that

x = 5.29449005

For c. begin by dividing both sides by 20 to get:

$\frac{1}{2}=e^{.1x}$

"Undo" that e by taking the ln of both sides:

$ln(.5)=ln(e^{.1x})$

When the ln and the e undo each other on the right you're left with just .1x; on the left we have, from our calculators:

-.6931471806 = .1x

x = -6.931471806

Question d. is a bit more complicated than the others. Begin by turning the base of 4 into a base of 2 so they are "like" in a sense:

$(2^2)^x-6(2)^x=-8$

Now we will bring over the -8 by adding:

$(2^2)^x-6(2)^x+8=0$

We can turn this into a quadratic of sorts and factor it, but we have to use a u substitution. Let's let $u=2^x$

When we do that, we can rewrite the polynomial as

$u^2-6u+8=0$

This factors very nicely into u = 4 and u = 2

But don't forget the substitution that we made earlier to make this easy to factor. Now we have to put it back in:

$2^x=4,2^x=2$

For the first solution, we will change the base of 4 into a 2 again like we did in the beginning:

$2^2=2^x$

Now that the bases are the same, we can say that

x = 2

For the second solution, we will raise the 2 on the right to a power of 1 to get:

$2^x=2^1$

Now that the bases are the same, we can say that

x = 1

5 0

3 years ago