Suppose f(x)= 2 ^ x - 3x and g(x = 1 - 2x. Find each of the following functions. a. (f + g)(x) b. (f- g)(x)

Mathematics

1 answer:

bearhunter [10]3 years ago

6 0

Answer:

(f+g)(x)=2^x-5x+1 and

(f-g)(x)=2^x-x-1

Step-by-step explanation:

(f+g)(x)=2^x-3x+1-2x

=2^x-5x+1

(f-g)(x)=2^x-3x-1+2x2x

=2^x-x-1

You might be interested in

Simplify the following, leaving your answer with a positive exponent: <br> x^-12/ x^-7

storchak [24]

Answer:

$\frac{1}{x^{5} }$

Step-by-step explanation:

x^-12/ x^-7

= x^(-12-(-7))

= x^-5

= 1/x^5

3 0

3 years ago

Not sure what this question is asking...

zalisa [80]

3)

$\bf ~~~~~~~~~~~~\textit{negative exponents}\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
\cfrac{-9}{2x^5}\implies \cfrac{-3^2}{2x^5}\implies \cfrac{-3^2}{1}\cdot \cfrac{1}{2}\cdot \cfrac{1}{x^5}\implies -\cfrac{1}{3^{-2}}\cdot 2^{-1}\cdot x^{-5}
\\\\\\
-\cfrac{2^{-1}x^{-5}}{3^{-2}}$

4)

$\bf 5^{-2}+5^0\implies \cfrac{1}{5^2}+1\implies \cfrac{1}{25}+1\implies \cfrac{1+25}{25}\implies \cfrac{26}{25}$

6 0

3 years ago

Pls help me<br><br> What is the awners

GenaCL600 [577]

Step-by-step explanation:

I didn't understand the question.

Do u want the function?

if so

$y = ax + b$