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Readme [11.4K]
3 years ago
5

Suppose f(x)= 2 ^ x - 3x and g(x = 1 - 2x. Find each of the following functions. a. (f + g)(x) b. (f- g)(x)

Mathematics
1 answer:
bearhunter [10]3 years ago
6 0

Answer:

(f+g)(x)=2^x-5x+1 and

(f-g)(x)=2^x-x-1

Step-by-step explanation:

(f+g)(x)=2^x-3x+1-2x

=2^x-5x+1

(f-g)(x)=2^x-3x-1+2x2x

=2^x-x-1

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Answer: 30 students per bus

Step-by-step explanation: 99-9=90

90/3=30

30 students per bus

8 0
3 years ago
2x^2=9-3x <br> Find the factors
d1i1m1o1n [39]

Answer:

x = -3, $ \frac{3}{2} $

Step-by-step explanation:

The given quadratic equation is: $ 2x^2 = 9 - 3x $

This can be written as: $ 2x^2 + 3x - 9 = 0 $

To solve a quadratic equation of the form $ ax^2 + bx + c = 0 $ we use the formula:

           $ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} $

Here, a = 2; b = 3; c = - 9

Therefore, the roots of the equation are:

$ x = \frac{- 3 \pm \sqrt{9 - 4(2)(-9)}}{2(2)} $

$ \implies x = \frac{-3 \pm \sqrt{81}}{4} $

$ \implies x = \frac{-3 \pm 9}{4} $

We get two values of 'x', viz.,

x = $ \frac{-3 + 9}{4} $ and $ \frac{- 3 - 9}{4} $

$ \implies x = \frac{6}{4} \hspace{5mm} \& \hspace{5mm} \frac{-12}{4} $

⇒ x = -3, 3/2

Since the factors of the quadratic equation is asked, we write it as:

(x + 3)(x - $ \frac{3}{2} $) = 0

because, if (x - a)(x - b) are the factors of a quadratic equation, then 'a' and 'b' are its roots.

Multiply (x + 3) and (x - $ \frac{3}{2} $ to see that this indeed is the given quadratic equation.

5 0
3 years ago
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Answer:

x= -2

Step-by-step explanation:

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Answer: is there suposed to be a symbol between the 2x and the 2?

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3 years ago
Casey's sister is 3 times as old as he is. His sister is 21 years old. Let c represent Casey's age. Which of the following would
algol13

Answer:

casey's age is 7

Step-by-step explanation:

if his sister is 3 times as old as he is then she is older therefore you would devide.

21/3=7

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