Can someone help its due soon

<img src="https://tex.z-dn.net/?f=If%20w%3D2x%2C%20then%20%5Cint%5Climits%5E2_0%20%7Bf%282x%29%7D%20%5C%2C%20dx%20%3D" id="TexFo

elena-14-01-66 [18.8K]

First, you should solve for $f(2x)$ , which equals $2*(2x)=4x$ . Now, solve the integral of $f(2x)$ = $2*(2x)=4x$ , to get that $\int\ {(f(2x)=4x)} \, dx= 2x^2$ . You can check this by taking the integral of what you got. Now by the Fundamental Theorem $\int\limits^2_0 {4x} \, dx=[2x^2] ^{2}_{0}=2(2)^{2}-2(0)^2=8$ .

This should be the answer to your question, if I understood what you were asking correctly.

8 0

3 years ago

Danielle worked three days last week for a total of 18.25 hours. She worked 6.5 hours on Monday and 5.75 hours on Wednesday. How

svet-max [94.6K]

Answer:

She worked for 6 hours on Saturday.

Step-by-step explanation:

Number of hours worked by Danielle last week = 18.25 hours

She worked for three days, Monday, Wednesday and Saturday.

Let she worked on Saturday = x hours

Therefore, total hours worked by Danielle in three days = 6.5 + 5.75 + x

And the equation will be,

6.5 + 5.75 + x = 18.25

12.25 + x = 18.25

x = 18.25 - 12.25

x = 6

Therefore, she worked for 6 hours on Saturday.

7 0

3 years ago

A patient is instructed to take three 50-mcg tablets of pergolide mesylate (Permax) daily. How many milligrams of the drug would

Black_prince [1.1K]

Answer:

The patient would receive 1.05mg of the drug weekly.

Step-by-step explanation:

First step: How many mcg of the drug would the patient receive daily?

The problem states that he takes three doses of 50-mcg a day. So

1 dose - 50mcg

3 doses - x mcg

x = 50*3

x = 150 mcg.

He takes 150mcg of the drug a day.

Second step: How many mcg of the drug would the patient receive weekly?

A week has 7 days. He takes 150mcg of the drug a day. So:

1 day - 150mcg

7 days - x mcg

x = 150*7

x = 1050mcg

He takes 1050mcg of the drug a week.

Final step: Conversion of 1050 mcg to mg

Each mg has 1000 mcg. How many mg are there in 1050 mcg? So

1mg - 1000 mcg

xmg - 1050mcg

1000x = 1050

$x = \frac{1050}{1000}$

x = 1.05mg

The patient would receive 1.05mg of the drug weekly.

6 0

4 years ago

What is 4(a5+7)+6(b7-5)

Andrej [43]

4a5+28+6b7-30
4a5+6b7-2<—- this is a to the power of 5 , b to the power of 7
(Is that 5a or a to the power of 5 )
20a+28+42b-30
20a+42b-2<—— this is 5a , 7b

4 0

3 years ago

Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118. If a recent test-taker

LuckyWell [14K]

Answer:

Probability that the student scored between 455 and 573 on the exam is 0.38292.

Step-by-step explanation:

We are given that Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118.

Let X = Math scores on the SAT exam

So, X ~ Normal( $\mu=514,\sigma^{2} =118^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean score = 514

$\sigma$ = standard deviation = 118

Now, the probability that the student scored between 455 and 573 on the exam is given by = P(455 < X < 573)

P(455 < X < 573) = P(X < 573) - P(X $\leq$ 455)

P(X < 573) = P( $\frac{X-\mu}{\sigma}$ < $\frac{573-514}{118}$ ) = P(Z < 0.50) = 0.69146

P(X $\leq$ 2.9) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{455-514}{118}$ ) = P(Z $\leq$ -0.50) = 1 - P(Z < 0.50)

= 1 - 0.69146 = 0.30854

The above probability is calculated by looking at the value of x = 0.50 in the z table which has an area of 0.69146.

Therefore, P(455 < X < 573) = 0.69146 - 0.30854 = 0.38292

Hence, probability that the student scored between 455 and 573 on the exam is 0.38292.

7 0

4 years ago