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xenn [34]
3 years ago
14

Harold took five different samples of thirty-five randomly selected students from the 520 students he surveyed. The means of the

samples are shown below.
Sample 1 mean = 3.4
Sample 2 mean = 3.2
Sample 3 mean = 4.1
Sample 4 mean = 4.6
Sample 5 mean = 3.1

The predicted mean of the population will fall between 3.1 and _______.

O 1.5
O 3.4
O 3.7
O 4.6
Mathematics
2 answers:
Sholpan [36]3 years ago
6 0
4.6 the answer is that
il63 [147K]3 years ago
4 0

Answer:

Answer: d)In repeated samples of the same size, approximately 95 percent of the intervals constructed from the samples will capture the population difference in means.

Explanation:

If we construct 100 of the given confidence interval, we are confident that 95% of them would contain the true population parameter. Therefore, the correct option is

d)In repeated samples of the same size, approximately 95 percent of the intervals constructed from the samples will capture the population difference in means.

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The equivalent expression

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Assuming your expression is \log_{15}2^3, then we can use the power property of logarithm , which is \log_ab^n=n\log_ab.

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Then using the power property of logarithm will give us:

\log_{15}2^3=3\log_{15}2

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</span><span>4x + 3y = 12
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</span>
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