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vodomira [7]
3 years ago
5

Prove the given trigonometric equation.

Mathematics
1 answer:
AURORKA [14]3 years ago
3 0

Answer:

Proving an identity is very different in concept from solving an equation.

Step-by-step explanation:

because it Though you'll use many of the same techniques, they are not the same, and the differences are what can cause you problems.

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In a bag of 50 marbles, 20 marbles are blue or pink.
Scorpion4ik [409]

Answer:

40%

Step-by-step explanation:

The ratio is 20:50, we can expand to 40:100, so 40%

8 0
2 years ago
Find RS. A. 5 B. 10 C. 9 D. 12
777dan777 [17]

Answer:

x=9

Step-by-step explanation:

PQ + QR + RS = PS

2x-6 + 1 + x-4 = 18

Combine like terms

3x -9 = 18

Add 9 to each side

3x-9+9= 18-9

3x = 27

Divide by 3

3x/3 = 27/3

x = 9

5 0
3 years ago
Read 2 more answers
5
Daniel [21]

Answer:

a,c,d

Step-by-step explanation:

8 0
2 years ago
Tao wants to check that the expression 3(4x – 6) simplifies to 12x – 18. What is the value when 2 is substituted for x into both
timurjin [86]

Answer:

6

Step-by-step explanation:

3( 4x - 6)

Let x =2

3( 4*2 -6)

3(8-6)

3*2

6

Check

12x-18

12*2 -18

24-18

6

Both equal 6

4 0
3 years ago
Which is equivalent to RootIndex 5 StartRoot 1,215 EndRoot Superscript x?
SOVA2 [1]

Answer:

1,215 Superscript one-fifth x

Step-by-step explanation:

Given:

The expression to simplify is given as:

(\sqrt[5]{1215})^x

We know that,

\sqrt[n]{a} = a^{\frac{1}{n}}

Here, n=5, a=1215

So, \sqrt[5]{1215} = 1215^{\frac{1}{5}}

So, the above expression becomes:

(\sqrt[5]{1215})^x = (1215^{\frac{1}{5}})^x

Now, using the law of indices (a^m)^n=a^{(m\times n)}

Here, a=1215,m=\frac{1}{5},n=x

So, the expression is finally simplified to;

=(1215)^{({\frac{1}{5}}\times x)}\\\\=(1215)^{\frac{1}{5}x}

Therefore, the second option is the correct one.

(\sqrt[5]{1215})^x = 1,215 Superscript one-fifth x

6 0
3 years ago
Read 2 more answers
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