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3 years ago

Prove the given trigonometric equation.

Mathematics

1 answer:

AURORKA [14]3 years ago

3 0

Answer:

Proving an identity is very different in concept from solving an equation.

Step-by-step explanation:

because it Though you'll use many of the same techniques, they are not the same, and the differences are what can cause you problems.

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In a bag of 50 marbles, 20 marbles are blue or pink.

Scorpion4ik [409]

Answer:

40%

Step-by-step explanation:

The ratio is 20:50, we can expand to 40:100, so 40%

8 0

2 years ago

Find RS. A. 5 B. 10 C. 9 D. 12

777dan777 [17]

Answer:

x=9

Step-by-step explanation:

PQ + QR + RS = PS

2x-6 + 1 + x-4 = 18

Combine like terms

3x -9 = 18

Add 9 to each side

3x-9+9= 18-9

3x = 27

Divide by 3

3x/3 = 27/3

x = 9

5 0

3 years ago

Read 2 more answers

Daniel [21]

Answer:

a,c,d

Step-by-step explanation:

8 0

2 years ago

Tao wants to check that the expression 3(4x – 6) simplifies to 12x – 18. What is the value when 2 is substituted for x into both

timurjin [86]

Answer:

Step-by-step explanation:

3( 4x - 6)

Let x =2

3( 4*2 -6)

3(8-6)

3*2

Check

12x-18

12*2 -18

24-18

Both equal 6

4 0

3 years ago

Which is equivalent to RootIndex 5 StartRoot 1,215 EndRoot Superscript x?

SOVA2 [1]

Answer:

1,215 Superscript one-fifth x

Step-by-step explanation:

Given:

The expression to simplify is given as:

$(\sqrt[5]{1215})^x$

We know that,

$\sqrt[n]{a} = a^{\frac{1}{n}}$

Here, $n=5, a=1215$

So, $\sqrt[5]{1215} = 1215^{\frac{1}{5}}$

So, the above expression becomes:

$(\sqrt[5]{1215})^x = (1215^{\frac{1}{5}})^x$

Now, using the law of indices $(a^m)^n=a^{(m\times n)}$

Here, $a=1215,m=\frac{1}{5},n=x$

So, the expression is finally simplified to;

$=(1215)^{({\frac{1}{5}}\times x)}\\\\=(1215)^{\frac{1}{5}x}$

Therefore, the second option is the correct one.

$(\sqrt[5]{1215})^x$ = 1,215 Superscript one-fifth x

6 0

3 years ago

Read 2 more answers