You have two equations.
since the second is already isolated, sub in x-4 for every y in equation 1 so that
![x^{2} - 4 [(x-4)^{2}] =16 ](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20-%204%20%5B%28x-4%29%5E%7B2%7D%5D%20%3D16%0A%20)
expand, collect like terms, factor to find x, then plug x value back into original equation to find y
Given that the first spinner has three equal sectors labelled 1, 2 and 3; and the second spinner has equal sectors labelled 3, 4, 5 and 6.
The number of possible outcomes that do not show a 1 on the first spinner is 2 (i.e. the first spinner shows 2 or 3).
The number of possible outcomes that the second spinner show the number 4 is 1 (i.e. the second spinner shows 4)
In probability, the word 'and' goes with multiplication.
Therefore, <span>the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner</span> is given by 2 x 1 = 2 possible outcomes.
i.e. the first spinner shows the number 2 and the second spinner shows the number 4 or the first spinner shows the number 3 and the second spinner shows the number 4.
The answer is : X=-7/3-2/3y
Answer:
x=75
Step-by-step explanation:
Hey There!
If you didn't know the exterior angle of a triangle is equal to the sum of the opposite interior angles of a triangle
So essentially what I'm saying is that
2x-5=70+x
step 1 add 5 to each side
-5+5 cancels out
70+5=75
now we have
2x=70+x
step 2 subtract x from each side
x-x cancels out
2x-x=x
we're left with
x=75
