All categories

3 years ago

What does X =? 5x−2=−10−3x

Mathematics

2 answers:

Alenkasestr [34]3 years ago

5 0

Answer:

x = -1

Step-by-step explanation:

kirill115 [55]3 years ago

3 0

5x-2=10-3x
8x=-8
8x/8=-8/8
X=-1

You might be interested in

Three units to the right of seven is?

KonstantinChe [14]

Answer:

10 i think

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

At a certain electronics company, the daily output Q is related to the number of people A on the assembly line by Q=600+√(A+41).

Ber [7]

Answer:

$A=400\ people$

Step-by-step explanation:

we have

$Q=600+\sqrt{A+41}$

where

Q -----> is the daily output

A -----> is the number of people

For Q=621

Find the value of A

substitute and solve for A

$621=600+\sqrt{A+41}$

Subtract 600 both sides

$621-600=\sqrt{A+41}$

$21=\sqrt{A+41}$

squared both sides

$21^{2} ={A+41}$

$441={A+41}$

Subtract 41 both sides

$441-41=A$

Rewrite

$A=400\ people$

3 0

3 years ago

Apply the distributive property to the expression 9(6m-4n). DO NOT SYMPLIFY.

zloy xaker [14]

Answer:

54m-36n

Step-by-step explanation:

9·6m= 54m

9·(-4n)= -36n

54m-36n

6 0

3 years ago

A. Show

nydimaria [60]

a. Recall the double angle identities:

$\sin^2x=\dfrac{1-\cos2x}2$

$\cos^2x=\dfrac{1+\cos2x}2$

Then

$\sin^2x\cos^2x=\dfrac{(1-\cos2x)(1+\cos2x)}4=\dfrac{1-\cos^22x}4$

Applying the identity again, we have

$\sin^2x\cos^2x=\dfrac{1-\frac{1+\cos4x}2}4=\dfrac{2-(1+\cos4x)}8=\dfrac{1-\cos4x}8$

as required.

b. Using the result from part (a),

$\sin^2x\cos^2x=\dfrac{1-\cos4x}8=\dfrac{2-\sqrt2}{16}$

$\implies\cos4x=\dfrac1{\sqrt2}$

$\implies4x=\dfrac\pi4+2n\pi\text{ or }4x=-\dfrac\pi4+2n\pi$

(where $n$ is any integer)

$\implies\boxed{x=\pm\dfrac\pi{16}+\dfrac{n\pi}2}$

8 0

3 years ago

The sum of three times d and 5 is 17

lakkis [162]

3d + 5 =17 - 5 - 5 3d / 3 12 / 3 d = 4

4 0

4 years ago