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vfiekz [6]
3 years ago
9

What is the total area of this composite figure rounded to the nearest hundredth?

Mathematics
1 answer:
Alex777 [14]3 years ago
5 0

Answer:

39.53 ft^2

Step-by-step explanation:

We can find the area of the rectangle

A = l*w

   = 12*3 = 36

And the area of the semicircle

A = 1/2 pir^2

The diameter is 3, the radius is 3/2

   =1/2 pi* (3/2)^2

   = 1/2 *3.14 * 9/4

3.5325

Add the two areas together

36+3.532539.5325

Rounding to the nearest hundredth

39.53 ft^2

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The area of a rectangular wall of a barn is 85 square feet. Its length is 12 feet longer than the width. Find the length and wid
MaRussiya [10]

Answer:

Length = 17 feet, Width = 5 feet

Step-by-step explanation:

Given:

The area of a rectangular wall of a barn is 85 square feet.

Its length is 12 feet longer than the width.

Question asked:

Find the length and width of the wall of the barn.

Solution:

Let width of a rectangular wall of a barn = x

<u>As length is 12 feet longer than the width.</u>

Length of a rectangular wall of a barn = 12+x

As we know:

Area\ of\ rectangle=length\times breadth

85=(12+x)x\\\\85=12x+x^{2} \\

Subtracting both sides by 85

x^{2} +12x-85=0\\x^{2} +17x-5x-85=0\\Taking\ common\\x+(x+17)-5x(x+17)=0\\(x+17)(x-5)=0\\x+17=0, x-5=0\\x=-17,x=5

As width can never be in negative, hence  width of a rectangular wall of a barn = x = 5 feet

Length of a rectangular wall of a barn = 12+x=12+5=17\ feet

Therefore, length and width of the wall of the barn is 17 feet and 5 feet respectively.

                 

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Step-by-step explanation:

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Answer:

Option 2  50 ≤ s ≤ 100

Option 5 She could deposit $50

Option 6 She could deposit $75

Step-by-step explanation:

Let

s -----> amount of money Layla deposit into a saving account

we know that

25%=25/100=0.25

50%=50/100=0.50

so

s\geq 0.25*200 -----> s\geq \$50

s\leq 0.50*200 -----> s\leq \$100

The compound inequality is

\$50 \leq s\leq \$100

<em>Verify each case</em>

case 1) 25 ≤ s ≤ 50

The statement is false

see the procedure

case 2) 50 ≤ s ≤ 100

<u>The statement is True</u>

see the procedure

case 3) s ≤ 25 or s ≥ 50

The statement is false

Because is s ≤ 100 and  s ≥ 50

case 4) s ≤ 50 or s ≥ 100

The statement is false

Because is s ≤ 100 and  s ≥ 50

case 5) She could deposit $50

<u>The statement is true</u>

Because the value of s satisfy the compound inequality  \$50 \leq s\leq \$100

case 6) She could deposit $75

<u>The statement is true</u>

Because the value of s satisfy the compound inequality  \$50 \leq s\leq \$100

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