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BigorU [14]
3 years ago
10

Please help as soon as possible

Mathematics
2 answers:
Marina CMI [18]3 years ago
7 0

Answer: 96 ft2.....12ft* 8ft = 96ft

Step-by-step explanation: hope it helps ur question

eduard3 years ago
4 0

Answer:

it's 96ft squared hope it helps

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3.5 squared. 12.25 times more would be the answer.
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25^x = 1 find the value of x
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Step-by-step explanation:

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An arc of length 15ft subtends a central angle 0 in a circle of radios 9ft. Find measure of 0 in degrees
Kisachek [45]

Answer:

95.49°

Step-by-step explanation:

The arc length formula is s = rФ, where r is the radius and Ф is the central angle in radians.  Here, r = 9 ft and s = 15 ft.  Thus, the central angle Ф is

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      3       π rad

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4 years ago
The graph of y=ax^2+bx+c passes through points (0,5), (1,10), and (2,19). Find a+b+c.
nataly862011 [7]

Answer:   a = 2   b = 3   c = 5  

Literally a+ b+c = 10, but I don't think that's what the question means to ask.

the equation is 2x² +3x + 5

Step-by-step explanation:   Substitute the values of the given coordinates into the formula and use algebra (solve a system of equations by substitution and elimination) to get the values  of a,b & c

y=ax²+bx+c    using  (0,5), (1,10), and (2,19)

5=a(0)²+b(0)+c   becomes 5= 0+0 + c .so we find c = 5

10=a(1)²+b(1)+c    becomes 10 = a + b + c

19=a(2)²+b(2)+c .  becomes 19 = 4a + 2b + c

Substitute the 5 for c.  Then rewrite

10 = a + b + 5      becomes     5 = a+ b     to eliminate b multiply this be (-2)

(-2)( 5 = a+ b) .to get -10 = -2a - 2b  

19 = 4a + 2b + 5  becomes   14 = 4a + 2b  

_______________  Add these two

14 = 4a + 2b

<u>-10 = -2a - 2b</u><u> </u>    this will eliminate the "b" term

4 = 2a       divide both sides by 2   so you have   a = 2  

substitute in 10=a(1)²+b(1)+5 to find b

10=2(1)²+b(1)+5 .becomes  5 = 2 + b   Subtract 2 from both sides

b = 3

So now you have all three values:  

a = 2  b= 3  c = 5  

I am attaching the graph. I hope this deserves Brainiest.

Best wishes in your studies!

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I am pretty sure it is linear decrease,
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