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4 years ago

PLEASE Help!! 20 Points!

Mathematics

1 answer:

omeli [17]4 years ago

8 0

An Expression is a group of numbers, variables, and operators. An equation is described as a mathematical statement.

Hope this helps

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Suppose a cheetah could travel 1.5 hours a top speed covering 111.9 miles how far could the cheetah travel in 1 hour

Luda [366]

$\bf \begin{array}{ccll}
hours&miles\\
\cline{1-2}
1.5&111.9\\
1&m
\end{array}\implies \cfrac{1.5}{1}=\cfrac{111.9}{m}\implies m=\cfrac{1\cdot 111.9}{1.5}\implies m=74.6$

4 0

4 years ago

Indicate the method you would use

Alexeev081 [22]

Answer:

<em> SSS</em><em> can be used to prove that the given triangles are congruent.</em>

Step-by-step explanation:

In the given two triangles ΔADC and ΔABC,

AD = AB = 7 units,
CD = BC = 8 units,
AC is common to both triangles,

Hence, ΔADC ≅ ΔABC by Side-Side-Side (SSS) congruence.

SSS congruence-

If three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent.

7 0

3 years ago

when the factors of a trinomial are (x+p) and (x-q) then the coefficient of the x-term of the trinomial is

inn [45]

Answer: the sum of p and q

Step-by-step explanation:

8 0

3 years ago

Ryan had 4 pieces of pipe that were each 1 1/3 yd long. He also had a piece of wood that was 4 1/6 yd long. Ryan needed to cut t

Andru [333]

4 pieces of pipe,

4/3 yd long

25/6 yd long

5 pieces same length.

(25/6)/5 = 5/6 yd is the length of each piece of woods.

3 0

3 years ago

Read 2 more answers

A calculator is required to obtain the final answer on this question. A solid metal sphere at room temperature 20oC is dropped i

yKpoI14uk [10]

Answer:

T = 47.1875°C

Step-by-step explanation:

Given:

Surrounding temp, Ts = 100°C

Initial Temperature ,T0= 20°C

Increase in temperature = 15°C

Final temperature, T = 20 + 15 = 35°C

Time, t = 9 seconds

Let's take Newton's law of cooling:

$T - Ts = (T_0 - Ts)e^k^t$

We'll solve for k

$35 - 100 = (20 - 100)e^9^k$

$-65 = (-80)e^9^k$

Divide both sides by -5

$13 = (16)e^9^k$

$9k = ln (\frac{13}{16})$

$k = \frac{1}{9} ln (\frac{13}{16})$

$k = -0.02307104053$

Let's now find the temperature of the ball after 18 seconds in boiling water.

Use the Newton's equation again:

$T - Ts = (T_0 - Ts)e^k^t$

$T - 100 = (20 - 100)e^-0.0^2^3^0^7^1^0^4^0^5^3^*^1^8$

$T - 100 = (-80)e^-0.0^2^3^0^7^1^0^4^0^5^3^*^1^8$

$T - 100= -52.8125$

$T = 100 - 52.8125$

T = 47.1875°C

Temperature of the ball after 18 seconds in boiling water is 47.1875°C

5 0

4 years ago