Answer:
Component form : (-7 , 2)
Step-by-step explanation:
P(4 , 5) = P'(4 +x , 5+y) = P'(-3 , 7)
4 + x = -3
x = -3 - 4
x = -7
5 + y = 7
y = 7 - 5
y = 2
Vector form : -7i + 2j
Component form : (-7 , 2)
Answer:
The first one and the last one
Step-by-step explanation:
To sub x>0 and x<0 into every functions.
Then, u will get some function that y doesn't have a negative value or positive value.
Then, these function doesn't fulfill the range.
Then, u will get the answer.
Answer:
D) 1/4
Step-by-step explanation:
To solve this, first lets figure out what this variable is. We know we must multiply by t. Well, looking at it, we know that t is one. So lets plug that in.
2*1/2^3(1)
Now we need to figure out what the exponent is that 2 will be raised to. To find that, find out what 3 times one is.
2*1/2^3
Now we need to solve the exponent.
2*1/8
Remember, 2 cubed is eight.
Now we need to find out what 2*1/8 is. To solve this more easily, I am going to turn two into a fraction. This will give us 2/1*1/8. Now we cross multiply, multiplying the numerators by the numerators, and the denominators by the denominators. Remember, the numerator is the top number, and the denominator is the bottom number.
If we do that, we get:
2/8
If we simplify it, we get 1/4. So the asnwer is D) 1/4
Answer:
x = 18 or x = -12.
Step-by-step explanation:
||x-3|-5| = 10 only if |x-3|-5 = 10 or |x-3|-5 = -10, i.e., if |x-3|=15 or |x-3|=-5; but |x-3| cannot be equal to -5, because |x-3| should be a non-negative value. Therefore, the first equation is true only if |x-3|=15. |x-3| = 15 only if x-3 = 15 or x-3 = -15, i.e., x = 18 or x = -12. We can verify this in the following way: ||18-3|-5|=||15|-5|=|10|=10 and ||-12-3|-5|=||-15|-5|=|15-5|=|10|=10. This verify that our solution is correct.
If you have a value for a variable you plug that value in and see if the resulting answer is true.
