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sergejj [24]
3 years ago
7

Which equation is true of x is 3.5

Mathematics
2 answers:
In-s [12.5K]3 years ago
5 0

Answer:

B

Step-by-step explanation:

Because 4 times 3.5 equals 14 and minus 3 equals -11 so its B.

pychu [463]3 years ago
5 0

Answer:

Your answer is B.

Step-by-step explanation:

The reason is because:

3-4x=-11

turns to

-4x=-14

when you subtract 3 from both sides then divide both sides by negative 4

and you get:

x=-14/-4

if you simplify -14/-4 your final answer will be

7/2 which equals 3.5:    x=3.5

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evablogger [386]

For this case we have two functions of the form y = f (x). We must find the quotient of the following functions:

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So, we have by definition:

\frac {f (x)} {g (x)} = \frac {x + 2} {3x + 5}

Answer:

\frac {f (x)} {g (x)} = \frac {x + 2} {3x + 5}

with 3x + 5 different from zero, so that the function is defined

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Step-by-step explanation:

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How to find the perimeter of the triangle
Sliva [168]

Answer:

A. 26.2

Step-by-step explanation:

To find the perimeter of the triangle, you have to find the distances of all three lines and add them up.

<u>Line AB</u>

Let's start off by finding the distance of line AB.

We will use the formula, d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}.

Point A is (-2,5) and Point B is (4,-3).

To substitute the values, it will get to d = \sqrt{(4--2)^{2}+(-3-5)^{2}} which in other words is d = \sqrt{(4+2)^{2}+(-3-5)^{2}}.

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Now we have to solve the exponents which would get to d = \sqrt{36+64}.

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Now let's find the distance of line BC.

We will use the same formula, d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}.

Point B is (4,-3) and Point C is (0,-6).

To substitute the values, it will get to d = \sqrt{(0-4)^{2}+(-6--3)^{2}} which in other words is d = \sqrt{(0-4)^{2}+(-6+3)^{2}}.

Now we have to solve the parentheses to get d = \sqrt{(-4)^{2}+(-3)^{2}}.

Now we have to solve the exponents which would get to d = \sqrt{16+9}.

Now we have to simplify the square root to d = \sqrt{25}. In other words, that is d = 5.

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Now let's fine the distance of line AC.

We will use the same formula, d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}.

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Perimeter of Triangle ABC = Line AB + Line BC + Line AC.

Perimeter of Triangle ABC = 10 + 5 + 11.2

Perimeter of Triangle ABC = 26.2

Hope this helped! If not, please let me know <3

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