Answer:
I believe D I’m not sure though
Step-by-step explanation:
The ratio of length to width is 3/2. Let's set up equations of ratios using first the 25 cm length of the paper and then the 20 cm width:
3 25 cm
--- = ----------
2 x
Solving for x, 3x = 50 cm, and x =16 2/3 cm. This is possible, since 16 2/3 is less than the paper width 20 cm.
3 20 cm
--- = -----------
2 x
Solving for x: 3x = 40 cm; x = 40/3 cm, or x= 13 1/3 cm. This is possible, but does not make maximum use of the 20 by 30 cm paper.
Answer: the largest flag Jake can draw on the paper given is 20 cm (length) by 16 2/3 cm.
Until now, given a function <span>f(x)</span>, you would plug a number or another variable in for x. You could even get fancy and plug in an entire expression for x. For example, given <span>f(x) = 2x + 3</span>, you could find <span>f(y2 – 1)</span> by plugging<span> y2 – 1</span> in for x to get <span>f(y2 – 1) = 2(y2 – 1) + 3 = 2y2 – 2 + 3 = 2y2 + 1</span>.
In function composition, you're plugging entire functions in for the x. In other words, you're always getting "fancy". But let's start simple. Instead of dealing with functions as formulas, let's deal with functions as sets of<span> (x, y)</span><span> points </span>
<span>Hope this awnsers your question</span>
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Answer:
two dice are thrown, so S = {(1,1); (1,2); (1,3); ...;(6,5); (6,6)} ---> 36
the sum is 2, 4, 6
sum = 2 --> (1,1) ---> 1
= 4 --> (1,3); (2;2); (3,1) ---> 3
= 6 --> (1,5); (2,4); (3,3); (4;2); (5,1) ---> 5
⇒ = 9/36 = 1/4
Answer: 27.12
Step-by-step explanation:
32.01
-5.89
27.12