Answer:
DE = 55
Step-by-step explanation:
As you can see from the red marks showing that the lengths of each triangle are the same, it must also be true that E is equal to 55.
Answer: the tuition in 2020 is $502300
Step-by-step explanation:
The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500
The fee in 2018 is the 19th term of the sequence. Therefore,
T19 = $45,4120
n = 19
Therefore,
454120 = 20500 + (19 - 1) d
454120 - 20500 = 19d
18d = 433620
d = 24090
Therefore, an
equation that can be used to find the tuition y for x years after 2000 is
y = 20500 + 24090(x - 1)
Therefore, at 2020,
n = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
Answer:
f(x) = 150-25x
Step-by-step explanation:
200-50=150.
Take the 150 and insert it there.
Each lesson is $25, so you multiply 25 by 2 every lesson. Example= 150-25=125-25=100-75 and so on.
The number of customers served in the ice cream shop in June, July and August are 125, 25 and 250 customers respectively
<h3>How to write and solve equation?</h3>
let
- June = x
- July = x - 100
- August = 2x
- Total customers = 400
Total = June + July + August
400 = x + (x- 100) + 2x
400 = x + x - 100 + 2x
400 = 4x - 100
400 + 100 = 4x
500 = 4x
x = 500/4
x = 125
So,
June = x
= 125 customers
July = x - 100
125 - 100
= 25 customers
August = 2x
= 2(125)
= 250 customers
Learn more about equation:
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