I think you are missing part of the quaetion there are no triangles.
Answer:
Step-by-step explanation:
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![\frac{2x^2-10x+12}{x^2-4} *\frac{2+x}{3-x} \\=\frac{2[x^2-5x+6]}{x^2-2^2} *\frac{2+x}{-(-3+x)} \\=\frac{2[x^2-2x-3x+6]}{(x+2)(x-2)} *\frac{x+2}{-(x-3)} \\=\frac{2[x(x-2)-3(x-2)]}{(x+2)(x-2)} *\frac{x+2}{-(x-3)} \\=\frac{2(x-2)(x-3)}{(x+2)(x-2)} *\frac{x+2}{-(x-3)} \\=\frac{2}{-1} \\=-2](https://tex.z-dn.net/?f=%5Cfrac%7B2x%5E2-10x%2B12%7D%7Bx%5E2-4%7D%20%2A%5Cfrac%7B2%2Bx%7D%7B3-x%7D%20%5C%5C%3D%5Cfrac%7B2%5Bx%5E2-5x%2B6%5D%7D%7Bx%5E2-2%5E2%7D%20%2A%5Cfrac%7B2%2Bx%7D%7B-%28-3%2Bx%29%7D%20%5C%5C%3D%5Cfrac%7B2%5Bx%5E2-2x-3x%2B6%5D%7D%7B%28x%2B2%29%28x-2%29%7D%20%2A%5Cfrac%7Bx%2B2%7D%7B-%28x-3%29%7D%20%5C%5C%3D%5Cfrac%7B2%5Bx%28x-2%29-3%28x-2%29%5D%7D%7B%28x%2B2%29%28x-2%29%7D%20%2A%5Cfrac%7Bx%2B2%7D%7B-%28x-3%29%7D%20%5C%5C%3D%5Cfrac%7B2%28x-2%29%28x-3%29%7D%7B%28x%2B2%29%28x-2%29%7D%20%2A%5Cfrac%7Bx%2B2%7D%7B-%28x-3%29%7D%20%5C%5C%3D%5Cfrac%7B2%7D%7B-1%7D%20%5C%5C%3D-2)
k.
Answer: The measures of all the three angles are 24 , 60 and 96
Step-by-step explanation:
Since the measures are given in ratio form, the first thing is to find the total ratio, which is
2 + 5+ 8 = 15
Recall that the sum of angles in a triangle is 180 ,so to calculate each angle , we have
2/15 x 180 = 24
also , 5/ 15 x 180 = 60
Finally, 8/15 x 180 = 96
The triangle is obtuse , since it is having one angle greater than 90.
It can not be acute because of the existence of 96 , for a triangle to be acute , all the angles must be less than 90 , and it can not be right triangle because there is no existence of 90
The third answer (Dividing the area by the height, multiplying the quotient, etc) is correct.
If we multiply by the height, we receive an expression equal to the sum of the bases divided by two. Multiplying by two, we now have the sum of the bases. Subtracting one base gives the length of the other base.
