To triple this number, you can triple the whole number, triple the fraction, then add them together.
3*3=9
1/2*3=3/2 (or 1 1/2)
Add them together.
9+1 1/2= 10 1/2
Answer: 95.45 %
Step-by-step explanation:
Given : The distribution is bell shaped , then the distribution must be normal distribution.
Mean : ![\mu=\ 16](https://tex.z-dn.net/?f=%5Cmu%3D%5C%2016)
Standard deviation :![\sigma= 1.5](https://tex.z-dn.net/?f=%5Csigma%3D%201.5)
The formula to calculate the z-score :-
![z=\dfrac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
For x = 13
![z=\dfrac{13-16}{1.5}=-2](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B13-16%7D%7B1.5%7D%3D-2)
For x = 19
![z=\dfrac{19-16}{1.5}=2](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B19-16%7D%7B1.5%7D%3D2)
The p-value = ![P(-2](https://tex.z-dn.net/?f=P%28-2%3Cz%3C2%29%3DP%28z%3C2%29-P%28z%3C-2%29)
![0.9772498-0.0227501=0.9544997\approx0.9545](https://tex.z-dn.net/?f=0.9772498-0.0227501%3D0.9544997%5Capprox0.9545)
In percent, ![0.9545\times100=95.45\%](https://tex.z-dn.net/?f=0.9545%5Ctimes100%3D95.45%5C%25)
Hence, the percentage of data lie between 13 and 19 = 95.45 %
Standard algorithm i think
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The number of ways for which she could pick four colours if green must be one of them is; 10 ways.
<h3>How many ways can she picks four colours if green must be there?</h3>
It follows from the task that there are 6 colours in total that she could pick from.
Hence, since she needs four colours with green being one of them, it follows that she only has 3 colours to pick from 5.
Hence, the numbers of possible combinations is; 5C3 = 10 ways.
Read more on combinations;
brainly.com/question/2280043
#SPJ1
Answer:
no
Step-by-step explanation: