These two angles are alternate interior, meaning that they are the same.
Therefore, 11x-10 = 2x+17
Solve to get x = 3; the two angles both equal to 23 degrees
and since EGF and DGE together form 90, DGE = 90-23 = 67
Answer:
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Step-by-step explanation:
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Answer:
Explanation:
The car travel 10ft north then 15ft due west. In order to find the distance from starting point. We need to find the hypotenuse where the distance to north and west are the adjacent side.
We can use Pythagorean’s theorem according to that:
Let c be the distance from starting point.
And a and b be the distance travel to north and west.
a^2 + b^2 = c^2
10^2 + 15^2 = c^2
100 + 225 = c^2
325 = c^2
Sqrt(325) = c
5sqrt(13) = c
Therefore, the distance from starting point is 5sqrt(13) ft
2. Slope: -4, y-intercept: -2
Answer:
The Proof for question no 20 and 21 are below.
Step-by-step explanation:
20.
Given:
∠PTR≅∠RSP
PT ≅ RS
To Prove:
ΔPQT ≅ ΔRQS
Proof:
In ΔPQT and ΔRQS
Statements Reasons
1. ∠PTR ≅ ∠RSP 1 .Given
2. ∠PQT ≅ ∠ROS 2. Vertical Opposite Angle Theorem.
3. PT ≅ RS 3. Given
4. ΔPQT ≅ ΔRQS 4. By A-A-S Congruence Postulate ....Proved
21.
Given:
PO ≅ SO
O is the Mid Point of NT
To Prove:
∠N ≅ ∠T
Proof:
In ΔPON and ΔSOT
Statements Reasons
1. PO ≅ S O 1 .Given
2. ∠PON ≅ ∠SOT 2. Vertical Opposite Angle Theorem.
3. NO ≅ TO 3. O is the Mid Point of NT
4. ΔPON ≅ ΔSOT 4. By S-A-S Congruence Postulate
5. ∠N ≅ ∠T 5. Corresponding Parts of Congruent Triangles are Congruent .( CPCTC )...Proved
