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Lorico [155]
3 years ago
14

Can someone help me with this

Mathematics
1 answer:
vekshin13 years ago
4 0
2nd one is an Integer.
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20 POINTS!!! If you put $ 2 comma 700 a year for 3 years into an IRA that earns 3.3​% a​ year, how much will you have saved at t
inysia [295]

Answer:

At the end of 3 years, we could save upto $ 2975.4 with an interest rate of 3.3 %

Step-by-step explanation:

If we are putting $ 2700 into our IRA ( individual Retirement Account) for 3 years and we are earning 3.3% profit every year, we need to find the total amount saved at the end of 3 years.

Since the interest is calculated for more than 1 year, this is an example of compound interest.

The formula used is:

FV = P ( 1 + r/n) ^n^t

where FV = future value

P= Principal amount of money deposited

r= annual interest rate ( in decimal form)

n= number of times interest rate is compounded  (yearly)

t= time period

So for our given guestion:

P= $2,700

r = 3.3 % = 0.033

n= 1

t= 3

putting our values in the formula

FV = P ( 1 + r/n) ^n^t

FV = 2700 ( 1+ 0.033 / 1 ) ^ 1 ^* ^ 3

FV = 2700 (1.033) ^ 3

FV = 2975.4

So, at the end of 3 years, we could save upto $ 2975.4 with an interest rate of 3.3 %

4 0
3 years ago
If the length of diagonal of a square is 4√2 cm, find it's length, perimeter and area.​
Sonbull [250]

Answer:

As Per Provided Information

  • Length of diagonal of square is 4√2 cm

We have been asked to find the length , perimeter and area of square .

First let's calculate the side of square .

Using Formulae

\boxed{\bf \:Diagonal_{(Square)} \:  = side \sqrt{2}}

On substituting the value in above formula we obtain

\qquad\longrightarrow\sf  \:4 \sqrt{2}  = side \sqrt{2}  \\  \\  \\ \qquad\longrightarrow\sf  \:4  \cancel{\sqrt{2}} = side \cancel{ \sqrt{2}} \\  \\  \\  \qquad\longrightarrow\sf  \:side \:  = 4 \: cm

<u>Therefore</u><u>,</u>

  • <u>Length </u><u>of </u><u>its </u><u>side </u><u>is </u><u>4</u><u> </u><u>cm</u><u>.</u>

Finding the perimeter of square.

\boxed{\bf \: Perimeter_{(Square)} = 4 \times side}

Substituting the value we obtain

\qquad\longrightarrow\sf  \:Perimeter_{(Square)} \:  = 4 \times 4 \\  \\  \\ \qquad\longrightarrow\sf  \:Perimeter_{(Square)} = 16 \: cm

<u>Therefore</u><u>,</u>

  • <u>Perimeter </u><u>of </u><u>square </u><u>is </u><u>1</u><u>6</u><u> </u><u>cm </u><u>.</u>

Finding the area of square .

\boxed{\bf \: Area_{(Square)} =  {side}^{2}}

Substituting the value we get

\qquad\longrightarrow\sf  \:Area_{(Square)} \:  =  {4}^{2}  \\  \\  \\ \qquad\longrightarrow\sf  \:Area_{(Square)} = 16 \:  {cm}^{2}

<u>Therefore</u><u>,</u>

  • <u>Area </u><u>of</u><u> </u><u>square</u><u> </u><u>is </u><u>1</u><u>6</u><u> </u><u>cm²</u><u>.</u>
3 0
2 years ago
What is the ratio of 4/9 and 5/9 in simplest form
a_sh-v [17]
\dfrac{4}{9}:\dfrac{5}{9}=\dfrac{4}{9}\cdot\dfrac{9}{5}=\dfrac{4}{5}
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3 years ago
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First graph is the correct one !
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