In the above word problem, If she chooses the 8-inch tiles, she will need a quarter as many tiles as she would with 2-inch tiles, Quarter 8-inch tiles will cover the same area as one 2-inches.
<h3>What is the justification for the above?</h3>
Note that the area of the one 2-inch tiles is given as:
A1 = 4in²
The area of the quarter 8-inch tiles is:
A2 = 1/4 x 8 x 8
A2 = 16inch²
Divide both areas
A2/A1= 16/4
= 4
This implies she'll need four 2-inch tiles to cover the same amount of space as a quarter 8-inch tile.
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Full Question:
A homeowner is deciding on the size of tiles to use to fully tile a rectangular wall in her bathroom that is 80 inches by 40 inches. The tiles are squares and come in three side lengths: 8 inches, 4 inches, and 2 inches. State if you agree with each statement about the tiles. Explain your reasoning.
If she chooses the 8-inch tiles, she will need a quarter as many tiles as she would with 2-inch tiles,
Answer:
33y+16
Step-by-step explanation:
Break apart the problem:
-4(-4-7y)=16+28y
5y+16+28y=33y+16 (Add like terms)
The third answer
1 quarter, 6 dimes, 1 nickel, 7 pennies
The answer is 30. 360/12.
Answer:
28 grams
Step-by-step explanation:
8 x 3 = 24
24 + 4 = 28
