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3 years ago

Y = | x |, 4 units right, reflection over x-axis

1 answer:

4 0

The answer to that is to put a negative outside to make the reflection over the x-axis and to move it to the right you put a minus four Y= -|x-4|

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It is not possible to divide 5 by 0 because there is no number you can___ by 0 and get 5 .

elixir [45]

Answer:

multiply

Step-by-step explanation:

5 0

2 years ago

You and your friend are selling tickets to a charity event. You sell 11 adult tickets and 8 student tickets for $158. Your frien

svetlana [45]

So what we have to do to solve this problem is to write down those values in 2 equations (one that represents what you sold and the other what your friend sold) compare them and find how much each ticket is worth.
First equation : 11x + 8y = 158
Where x = how much each adult ticket is
and y = how much each student ticket is

The second equation is : 5x + 17y = 152

Using the method of substitution , we can compare each equation side by side:
11x + 8y = 158
5x + 17y = 152
Now we need to set one of the variables of both equations so they are equal:
11(5)x + 8(5) = 158(5)
5(11)x + 17(11)x = 152(11)

55x + 40y = 790
55x + 187y = 1672

Then we subtract the second equation by the first one

55x-55x + 187y - 40y = 1672 - 790
147y = 882
y = 6
The we apply y to one of the equations to discover x :
11x + 8y = 158
11x + 8(6) = 158
11x + 48 = 158
11x = 110
x = 10

So the awnser is :
Each adult ticket (x) is $10
And each student ticket (y) is $8
I hope you understood my explanation,

7 0

3 years ago

Read 2 more answers

PLEASE HELPTH ME (MODERATORS STOP I REPEAT STOP REMOVING MY QUESTIONS BRO)

kompoz [17]

Answer:

X=75

Y=110

Step-by-step explanation:

A straight line is 180, so add the equations that make a line and set them equal to 180

x+20+x+10=180

Combine like terms

2x+30=180

Subtract 30 from both sides

2x=150

Divide by 2

X=75

Same for y

y+y-40=180

2y-40=180

Add 40 to both sides

2y=220

Divide by 2

Y=110

5 0

3 years ago

A 100 gallon tank initially contains 100 gallons of sugar water at a concentration of 0.25 pounds of sugar per gallon suppose th

Vsevolod [243]

At the start, the tank contains

(0.25 lb/gal) * (100 gal) = 25 lb

of sugar. Let $S(t)$ be the amount of sugar in the tank at time $t$ . Then $S(0)=25$ .

Sugar is added to the tank at a rate of P lb/min, and removed at a rate of

$\left(1\frac{\rm gal}{\rm min}\right)\left(\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm gal}\right)=\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm min}$

and so the amount of sugar in the tank changes at a net rate according to the separable differential equation,

$\dfrac{\mathrm dS}{\mathrm dt}=P-\dfrac S{100}$

Separate variables, integrate, and solve for S.

$\dfrac{\mathrm dS}{P-\frac S{100}}=\mathrm dt$

$\displaystyle\int\dfrac{\mathrm dS}{P-\frac S{100}}=\int\mathrm dt$

$-100\ln\left|P-\dfrac S{100}\right|=t+C$

$\ln\left|P-\dfrac S{100}\right|=-100t-100C=C-100t$

$P-\dfrac S{100}=e^{C-100t}=e^Ce^{-100t}=Ce^{-100t}$

$\dfrac S{100}=P-Ce^{-100t}$

$S(t)=100P-100Ce^{-100t}=100P-Ce^{-100t}$

Use the initial value to solve for C :

$S(0)=25\implies 25=100P-C\implies C=100P-25$

$\implies S(t)=100P-(100P-25)e^{-100t}$

The solution is being drained at a constant rate of 1 gal/min; there will be 5 gal of solution remaining after time

$1000\,\mathrm{gal}+\left(-1\dfrac{\rm gal}{\rm min}\right)t=5\,\mathrm{gal}\implies t=995\,\mathrm{min}$

has passed. At this time, we want the tank to contain

(0.5 lb/gal) * (5 gal) = 2.5 lb

of sugar, so we pick P such that

$S(995)=100P-(100P-25)e^{-99,500}=2.5\implies\boxed{P\approx0.025}$

5 0

2 years ago

A ski resort has 18 inches of snow on the ground. The snow is falling at a rate of 4 inches per hour. which type of functions be

faust18 [17]

Answer:

Linear Function

$y=4x+18$

Step-by-step explanation:

Let

x----> the time in hours

y----> the total inches of snow on the ground

we know that

The function that best model this situation is the linear function

$y=mx+b$

In this problem

$m=4\frac{in}{h}$

$b=18\ in$ ----> the y-intercept

substitute

$y=4x+18$

4 0

3 years ago

Read 2 more answers