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horrorfan [7]
3 years ago
11

Y = | x |, 4 units right, reflection over x-axis

Mathematics
1 answer:
Dafna1 [17]3 years ago
4 0
The answer to that is to put a negative outside to make the reflection over the x-axis and to move it to the right you put a minus four Y= -|x-4|
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kolezko [41]

Answer:

$18.00

Step-by-step explanation:

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How to solve Help?<br> (14+x)^2= 25^2 +x^2
shusha [124]
<span>(14+x)^2= 25^2 +x^2
14^2 + 28x + x^2 = </span><span>25^2 +x^2
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How can the use of sine and cosine be helpful for determining what a triangle looks like?
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What is the orthocenter of a triangle with vertices A(−3,−2)A(−3,−2), B(−2,2)B(−2,2), and C(2,−2)C(2,−2)?
ExtremeBDS [4]

A(−3,−2), B(−2,2), C(2,−2)

The orthocenter is the meet of the altitudes. We see AC is parallel to the x axis so the perpendicular x=-2 is the altitude through B.

Between A and B we have slope (2 - -2)/(-2 - -3) = 4 so perpendicular slope -1/4 through C(2,-2):

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For the y coordinate of the orthocenter we substitute in x=-2.

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8 0
3 years ago
Please help quick.
GREYUIT [131]

Answer:

The answer to your question is: third option is correct

Step-by-step explanation:

Data

F (5, -1)

directrix   y = 1

Then, after getting the graph, the vertix = (5, 0)

                                                        and p = 1

                 Formula

                              (x - h) ² = -4p(y - k)

                              (x - 5)² = -4(1)(y - 0)

                              (x - 5)² = -4y

                              y = (x - 5)² / -4

3 0
3 years ago
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