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Makovka662 [10]
2 years ago
15

Find the value of x.

Mathematics
1 answer:
Maslowich2 years ago
6 0
The value of x is would be A
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WILL GIVE ALL MY POINTS working alone, machine a takes 2 hours to build a car, working alone machine b takes 3 hours to build a
kati45 [8]

Answer:

It will take Machine A 20 additional minutes.

Step-by-step explanation:

First we have get the rate of work per hour, Machine A builds 1/2 of a car per hour, while Machine B builds 1/3 of a car per hour.

Using this we can determine the amount of work that has been done so far in one hour before Machine B broke down:

1/2 + 1/3 = 3/6 + 2/6 = 5/6

Now we can produce an equation accordingly to determine how much time it'll take machine a to finish the job:

5/6 + 1/2x = 1

1/2x = 1/6

x = 1/3 hours = 20 minutes

Note: In the question you typed "how much additional time will it take machine b to finish" but I think you meant machine a because machine b broke down. Please correct me if I'm wrong.

Hope this helps! And let me know if you have any questions!

7 0
3 years ago
Which ratio is the simplest form of 42 : 28 ?<br> A) 2:1<br> B<br> 21:14<br> 3:2<br> 2<br> D) 2:3
Natalija [7]

Answer:

3/2

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What percent is equivalent to 1/20​
olganol [36]

Answer:

1/20 is 5%

Step-by-step explanation:

1/20 = 5%

20/20 = 100%

100 ÷ 20 = 5%

1/20 x 100 = 0.05 x 100 = 5%

5 0
3 years ago
Read 2 more answers
Add −2/3+2 3/8 . Write your answer as a mixed number in simplest form.
d1i1m1o1n [39]

Answer:

41/24 or 1 17/24

Step-by-step explanation:

2 3/8=19/8

-2/3+19/8

-16/24+57/24

41/24

5 0
2 years ago
Read 2 more answers
Find the max and min values of f(x,y,z)=x+y-z on the sphere x^2+y^2+z^2=81
Anton [14]
Using Lagrange multipliers, we have the Lagrangian

L(x,y,z,\lambda)=x+y-z+\lambda(x^2+y^2+z^2-81)

with partial derivatives (set equal to 0)

L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}
L_y=1+2\lambda y=0\implies y=-\dfrac1{2\lambda}
L_z=-1+2\lambda z=0\implies z=\dfrac1{2\lambda}
L_\lambda=x^2+y^2+z^2-81=0\implies x^2+y^2+z^2=81

Substituting the first three equations into the fourth allows us to solve for \lambda:

x^2+y^2+z^2=\dfrac1{4\lambda^2}+\dfrac1{4\lambda^2}+\dfrac1{4\lambda^2}=81\implies\lambda=\pm\dfrac1{6\sqrt3}

For each possible value of \lambda, we get two corresponding critical points at (\mp3\sqrt3,\mp3\sqrt3,\pm3\sqrt3).

At these points, respectively, we get a maximum value of f(3\sqrt3,3\sqrt3,-3\sqrt3)=9\sqrt3 and a minimum value of f(-3\sqrt3,-3\sqrt3,3\sqrt3)=-9\sqrt3.
5 0
3 years ago
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