A. 60(2/3) + 35(7/10) + 45(5/6) = $102.00
b. 60 + 35 + 45 = 140 = original price
140 - 102 = $30 saved
c. 102/140 = .7286 * 100 = 72.86 % (not sure how you need it rounded)
Obviously this will be a negative number
-2 - 14 = 5x - 3x
-16 = 2x
x = %28-16%29%2F2
x = -8 is the number
:
:
Check solution in the original statement: x=-8
3(-8) - 2 = 5(-8) + 14
-24 - 2 = -40 + 14
-26 = -26
The value of the derivative of the function g(x) at x = 1 will be 1/3. Then the correct option is A.
<h3>What is an inverse function?</h3>
A function that may convert into another function is known as an inverse function or anti-function.
If the function is f(x) = sinx + 2x + 1.
Then the derivative of an inverse function g(x) of a function f(x) at a given value (a) will be
The derivative of f(x) will be
f'(x) = cos x + 2
Then the given value of a will be
a = 1
g(x) = f⁻¹(x)
put x = 0, then we have
f(0) = sin 0 + 2(0) + 1
f(0) = 1
Put x = 1, in the function f⁻¹(x). Then we have
f⁻¹(1) = 0
and
g(1) = 0
Then put a = 1, then we have
More about the inverse function link is given below.
brainly.com/question/2541698
#SPJ4
13/35 because you have to find the common denominator which would be 35 and in order to get 7 to 35 you have to multiply the whole thing by 5 making the fraction equal 15/35 and you have to multiply the other fraction by 7 making it 7/35 add the two together which would equal 22/35 so to make that 35/35 it would have to be 13/35
That's a lot of points for this question. You don't have to offer that much.
Leading Coefficient: When written in standard form (starting with the variable with the highest power, going to the variable with the next highest power ... all the way down to a number with no variable), the leading coefficient is the number in front of the variable with the highest power.
Let me put this less technically. Find the variable with the highest power. The number in front of that variable is the leading coefficient.
Write this in standard form. 5x^4 -2x + 1
The number in front of the x^4 is the answer.
5 <<<<< answer
