Answer:
Jack in Zeta Labs near Facility Intelligence and Zeta Labs spawn (Sells gadgets like the Presence Reduction Module and Night Vision Goggles)
Step-by-step explanation:
if you do not have a Unit Circle, this is a great time to get one, you can find many online just do a quick search for "unit circle".
Check the picture below.
Answer:
y=-5/3x+20
Step-by-step explanation:
Let the equation of the required line be represented as ![\[y=mx+c\]](https://tex.z-dn.net/?f=%5C%5By%3Dmx%2Bc%5C%5D)
This line is perpendicular to the line ![\[y=\frac{3}{5}x+10\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B3%7D%7B5%7Dx%2B10%5C%5D)
![\[=>m*\frac{3}{5}=-1\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Em%2A%5Cfrac%7B3%7D%7B5%7D%3D-1%5C%5D)
![\[=>m=\frac{-5}{3}\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Em%3D%5Cfrac%7B-5%7D%7B3%7D%5C%5D)
So the equation of the required line becomes ![\[y=\frac{-5}{3}x+c\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-5%7D%7B3%7Dx%2Bc%5C%5D)
This line passes through the point (15.-5)
![\[-5=\frac{-5}{3}*15+c\]](https://tex.z-dn.net/?f=%5C%5B-5%3D%5Cfrac%7B-5%7D%7B3%7D%2A15%2Bc%5C%5D)
![\[=>c=20\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ec%3D20%5C%5D)
So the equation of the required line is ![\[y=\frac{-5}{3}x+20\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-5%7D%7B3%7Dx%2B20%5C%5D)
Among the given options, option 4 is the correct one.
Answer:
–16 – 22i
Step-by-step explanation:
The radius of the circle = 4 + 26i - (-6 + 2i)
= 10 + 24i.
The radius will be the absolute values of this |10 + 24i|.
If a point is on the circle then it's distance from the centre must be 10+ 24i.
-19 + 15i - (-6 + 2i) = -13 - 13i , so this is not on the circle.
-16 - 22i - (-6 + 2i) = -10 - 24i = |10 + 24i| , so this is on the circle.
5 + 16i - (-6 + 2i) = 11 + 14i , so this is not on the circle.
20 - 24i - (-6 + 2i) = 26 - 26i. so this is not on the circle.
Answer:
(5x+6)(2x+5)-(2x+4)(x+8) simplified is 8x^2+17x-2
Step-by-step explanation: