Answer:
im pretty sure its 152, im sorry if im wrong, i took 180 and subtracted 180 - 16 - 12 and got that soooo
Step-by-step explanation:
Answer:
a) P(X∩Y) = 0.2
b) 
= 0.16
c) P = 0.47
Step-by-step explanation:
Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.
So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67
Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:
P(X∩Y) = P(X) + P(Y) - P(X∪Y)
P(X∩Y) = 0.36 + 0.51 - 0.67
P(X∩Y) = 0.2
On the other hand, the probability that he must stop at the first signal but not at the second one can be calculated as:
= P(X) - P(X∩Y)
= 0.36 - 0.2 = 0.16
At the same way, the probability 
that he must stop at the second signal but not at the first one can be calculated as:
= P(Y) - P(X∩Y)
= 0.51 - 0.2 = 0.31
So, the probability that he must stop at exactly one signal is:
Answer:
C= 7y +150
850
250
Step-by-step explanation:
The cost is 7 times y, the number of yearbooks, plus 150, the upfront cost.
7 times 100 is 700, plus 150 is 850.
1900-150 is 1750 divided by 7 is 250
Answer:
8x -12
Step-by-step explanation:
Use the distributive property. 16 outside wishes to go inside and multiply each term; you get 16x/2 which is 8x minus ¾ of 16 which is 12.
Answer:
No
Step-by-step explanation:
The sequence is not an arithmetic sequence. For a sequence to be arithmetic, the difference between consecutive terms is a constant number which is termed as the common difference.
This means that the difference between the second term and the first term must be equal to the difference between the third term and the second term.
In the sequence above, the first term is 10. The difference between the first and second term is 15. When the first term is subtracted from the second, what we get is 5.
Now, let’s look at the third term and the second term. The difference here is 21 minus 15 which equals 6. Now we can see that the common difference is not constant and thus we conclude that the series is not arithmetic.
