(6 + 3) + 21 = 6 + (3 + 21)
It's an ASSOCIATIVE PROPERTY
(a + b) + c = a + (b + c)
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
Answer:
Step-by-step explanation:
I can't get to act correctly either.
The answer is 1 day and 7 items.
Ariana
y = 5x + 2
Julie
y = 7x
The ys have to be the same so equate the right hand side.
7x = 5x + 2 Subtract 5x from both sides.
7x - 5x = 5x - 5x + 2
2x = 2 Divide by 2
2x/2 = 2/2
x = 1
1 day
7 items
(x+7)(x+3) so therefore you set each equation = 0...
x + 7 = 0
x + 3= 0
and solve
x = -3
x = -7
Answer:
The probability that a family spends less than $410 per month
P( X < 410) = 0.1151
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given mean of the population = 500 </em>
<em>Given standard deviation of the Population = 75</em>
Let 'X' be the variable in normal distribution
<em>Given X = $410</em>
<em></em>
<em></em>
<u><em>Step(ii):-</em></u>
The probability that a family spends less than $410 per month
P( X < 410) = P( Z < - 1.2 )
= 0.5 - A( -1.2)
= 0.5 - A(1.2)
= 0.5 - 0.3849 ( ∵from normal table)
= 0.1151
<u>Final answer:-</u>
The probability that a family spends less than $410 per month
P( X < 410) = 0.1151
