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Tpy6a [65]
2 years ago
14

Ten pictures, each measuring 4 inches by 6 inches, are mounted on a piece of green poster board so that there is no overlap. The

poster board measures 20 inches by 17 inches. All the shapes are rectangular. How many square inches of the green background will show after the pictures are mounted
Mathematics
1 answer:
alexandr1967 [171]2 years ago
3 0

Answer:

100 square inches

Step-by-step explanation:

Dimension of each of the ten pictures= 4 inches by 6 inches

Area of one of the pictures=4*6=24 Square Inch.

Total Area of the 10 pictures=24*10=240 Square Inches.

Dimension of the Poster Board=20 inches by 17 inches.

Area of the Poster Board=20*17=340 Square Inches.

Area not covered by the pictures=340-240=100 Square Inches

Therefore, 100 square inches of the green background will show after the pictures are mounted.

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If one gallon of paint covers 825 sq. ft., how much paint is needed to cover 2640 sq. ft.?
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3.2 gallons

Step-by-step explanation:

2640 / 825 = 3.2

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When pointing A(-6. - 12) is reflected over the y-axis to get point B, what are the
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Answer:

A

Step-by-step explanation:

under a reflection in the y- axis

a point (x, y ) → (- x, y ) , then

A (- 6, - 12 ) → B (6, - 12 )

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2 years ago
If a small boy, in 30 days, saved $1.00 to spend in your store, how much did he save each day?
ivolga24 [154]

Answer:

3 cents for 29 days and 4 cents for 1 day

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1.00 dollar / 30 days = .03 cents

3 cents x 30 = .99 cents

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What fractions are equivalent to - 2/3
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- 4/6, -6/9, -8/12, -10/15, -12/18, -14/21, and more

5 0
2 years ago
Read 2 more answers
What are the values of m and n in the matrix addition below?
Aleksandr [31]

ANSWER

The correct answer is m=45,n=12.

<u>EXPLANATION</u>

We were given the matrix equation;

\left[\begin{array}{cc}n-1&6\\-19&m+3\end{array}\right] +\left[\begin{array}{cc}-1&0\\16&-8\end{array}\right] =\left[\begin{array}{cc}10&6\\-3&40\end{array}\right].


We must first simplify the Left Hand Side of the equation by adding corresponding entries.


\left[\begin{array}{cc}n-1+-1&6+0\\-19+16&m+3-8\end{array}\right]=\left[\begin{array}{cc}10&6\\-3&40\end{array}\right].


That is;


\left[\begin{array}{cc}n-2&6\\-3&m-5\end{array}\right]=\left[\begin{array}{cc}10&6\\-3&40\end{array}\right].

Since the two matrices are equal, their corresponding entries are also equal. we equate corresponding entries and solve for m and n.


This implies that;


n-2=10


We got this equation from row one-column one entry of both matrices.


n=12


Also, the row three-column three entries of both matrices will give us the equation;


m-5=40


m=45


Hence the correct answer is m=45,n=12.


The correct option is option 2






6 0
2 years ago
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