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Iteru [2.4K]
3 years ago
15

Match the type of graph with its description.

Mathematics
1 answer:
coldgirl [10]3 years ago
4 0

Answer:

1) Compares data that are in categories

2) Organises data into 4 groups of equal sizes and is often used to compare two sets of data.

3) Used to see trends in data.

4) Shows changes over time.

5) Shows the frequency of data using equal intervals with no space between the bars.

Step-by-step explanation:

1) Bar graph is used to compare data that are in categories

2) Box and whisker plot is used to organise data into 4 groups of equal size.

3) Line graph is basically used to see different trends.

4) Scatter plot is used to show changes that have occurred over time

5) Histogram is used to show the frequency of data using equal intervals with no space between the bars.

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What is the answer to 3x+x/4=x+3/4
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Answer:x = 1

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3x + x/4 = x + 3/4

Subtract x from each side

2x + x/4 = 3/4

Times each side by 4

The 4 beneath the x cancels out

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Divide each side by 3

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Round 637.892 to whole number
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638

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A certain firm has plants A, B, and C producing respectively 35%, 15%, and 50% of the total output. The probabilities of a non-d
Sliva [168]

Answer:

There is a 44.12% probability that the defective product came from C.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

-In your problem, we have:

P(A) is the probability of the customer receiving a defective product. For this probability, we have:

P(A) = P_{1} + P_{2} + P_{3}

In which P_{1} is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

P_{1} = 0.35*0.25 = 0.0875

P_{2} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{2} = 0.15*0.05 = 0.0075

P_{3} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{3} = 0.50*0.15 = 0.075

So

P(A) = 0.0875 + 0.0075 + 0.075 = 0.17

P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

So, the probability that the defective piece came from C is:

P = \frac{0.5*0.15}{0.17} = 0.4412

There is a 44.12% probability that the defective product came from C.

3 0
4 years ago
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