Answer: 81%
Step-by-step explanation:
From the question, we are informed that a student received the following test scores: 71%, 89%, 72%,
84% and 83% in 5 tests and the student wants to maintain an average of 80%.
The lowest score/grade they can receive on the next test to maintain at least an 80% average first thus:
First, to make it easy we can remove the percent sign. Then we multiply 80 by 6 since we're calculating for 6 tests scores. This will be:
= 80 × 6
= 480
We then add all the 5 test scores. This will be:
= 71 + 89 + 72 + 84 + 83
= 399
We then subtract the values gotten. This will be:
= 480 - 399
= 81
This means the student must get at least 81%
The correct answer is <span>R(x) = 9,000[9(1.035)x + 7(1.021)x]; $170,936</span>
Y=1/2x -3 find the x coordinate of the point whose y
coordinate is 5
y = 5. Write the equation as:
1/2F2x - 3 = 5
multiply both sides by 2, and you have
x - 6 = 10
x = 10 + 6
x - 16
Check solution in original equation, replace x with 16
y = 1/2F2(16) - 3
y = 8 - 3
y = 5
Answer:
the student should score atleast 229 to be among the top 10%.
Step-by-step explanation:
in terms of the normal distribution, and if the table that you're using calculates the area of the normal distribution from the mean to a point x, only then what we are actually finding the value 'x' at which the z-score is at 40% (the rest 50% is already skipped by the table)

after finding the the value at this z-score, we can find the value of x at which the score is in the top 10% range.
we can find the z-score either using a normal distribution table or calculator. (but be sure what area is it calculating)
looking at the table the closest value we can find is, 0.4015 at z = 1.29 ((it is above 40% because we want to be in the top 10% range)




the student should score atleast 229 to be among the top 10%.