2. y = -4x + 1 so slope m = -4
passing thru (3,-1)
y = mx + b
-1 = -4(3) + b
-1 = -12 + b
11 = b or b = 11
answer:
equation: y = -4x + 11
4.
answer is a. -2, 1/2 opposite reciprocal
b. 1/4 , 4 ..... only reciprocal
c. 5, -5..........only opposite
Answer:
<u>153 1/4 feet</u>
Step-by-step explanation:
Remaining
- 200 - 46 3/4
- <u>153 1/4 feet</u>
Answer:
See below ~
Step-by-step explanation:
<u>Details of the graph of the quadratic equation</u>
- Minimum value = <u>-1</u>
- Domain : <u>all real numbers</u>
- Range : <u>y ≥ -1</u>
Answer:
![157\ in^{2}](https://tex.z-dn.net/?f=157%5C%20in%5E%7B2%7D)
Step-by-step explanation:
we know that
The area of the figure is equal to the area of rectangle plus the area of two semicircles
<u>The area of rectangle is equal to</u>
![A=14*5=70\ in^{2}](https://tex.z-dn.net/?f=A%3D14%2A5%3D70%5C%20in%5E%7B2%7D)
<u>The area of the small semicircle is equal to</u>
![A=\pi r^{2} /2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E%7B2%7D%20%2F2)
-----> radius is half the diameter
substitute
![A=(3.14)(2.5^{2})/2=9.8125 in^{2}](https://tex.z-dn.net/?f=A%3D%283.14%29%282.5%5E%7B2%7D%29%2F2%3D9.8125%20in%5E%7B2%7D)
<u>The area of the larger semicircle is equal to</u>
![A=\pi r^{2} /2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E%7B2%7D%20%2F2)
-----> radius is half the diameter
substitute
![A=(3.14)(7^{2})/2=76.93\ in^{2}](https://tex.z-dn.net/?f=A%3D%283.14%29%287%5E%7B2%7D%29%2F2%3D76.93%5C%20in%5E%7B2%7D)
The area of the figure is equal to
![70+9.8125+76.93=156.7425=157\ in^{2}](https://tex.z-dn.net/?f=70%2B9.8125%2B76.93%3D156.7425%3D157%5C%20in%5E%7B2%7D)
Answer:
< PQR = 61°
Step-by-step explanation:
Hope this helps:)