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3 years ago

2a^(2) – (4b + c); a = –3, b = –2, and c = 1

Mathematics

1 answer:

vfiekz [6]3 years ago

3 0

Answer:

= 25

Step-by-step explanation:

2 (-3)^2 - (4(-2) + 1)

2 (9) - (-8 + 1)

18 - (-7)

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What is the following product? Assume x>/=0 ^3sqrt(x^2)*^sqrtx^3

RoseWind [281]

Answer:

$x(\sqrt[12]{x^5} )$

Step-by-step explanation:

We need to remember 2 rules when doing these:

1. $\sqrt[n]{x^a} =x^{\frac{a}{n}}$

2. $x^a*x^b=x^{ab}$

Using these 2 rules, we can simplify the product (steps shown below):

$\sqrt[3]{x^2} *\sqrt[4]{x^3} \\=x^{\frac{2}{3}}*x^{\frac{3}{4}}\\=x^{\frac{2}{3}+\frac{3}{4}}\\=x^{\frac{17}{12}}\\=x^{\frac{12}{12}+\frac{5}{12}}\\=x(x^{\frac{5}{12}})\\=x(\sqrt[12]{x^5} )$

Rearranging, we see that it is the third choice.

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3 years ago

Write the doubles minus one fact for 4+4

Vitek1552 [10]

4+4 =8
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Answer:

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Step-by-step explanation:

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3 years ago

I need help on number 2. A

Drupady [299]

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3 years ago

Ok I need to know if I did this right so: 8^0 = 1 right (exponents) please help

xxMikexx [17]

Answer:

Yes that's correct. I just took a test on this not to long ago and got a 100%. I had this type of problem.

Step-by-step explanation:

Hope this helps!

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