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RSB [31]
3 years ago
9

What is the length of segment AB?

Mathematics
1 answer:
Ilya [14]3 years ago
6 0

12!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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Lin and Claire each threw a rock into a stream. The black graph represents the height of a stone t seconds after it was tossed u
kotykmax [81]

Answer:

1) claire's stone at 1.25 seconds

2) 0.5 seconds and its max height was 9

3) lin at 8ft

Step-by-step explanation:

the intercepts tell you the first and third question and then the max height is the highest point on the graph

not sure what measurements you were supposed to use so I used seconds and feet and if that's not it then it's the same numbers just different words

4 0
3 years ago
What are the minimum and maximum distances that Morgan’s dog may be from the house? (Algebra ll) *URGENT*
Mashcka [7]

Given:

The minimum and maximum distance that the dog may be from the house can be found by using the equation:

|x-500|=8

To find:

The minimum and maximum distance that the dog may be from the house.

Solution:

We have,

|x-500|=8

It can be written as:

x-500=\pm 8

Adding 500 on both sides, we get

x=500\pm 8

Now,

x=500+8 and x=500-8

x=508 and x=492

The minimum distance is 492 meters and the maximum distance is 508 meters.

Therefore, the correct option is C.

6 0
3 years ago
A rectangle has side lengths of (3x+6) inches and (2x-4) inches. Write an expression to represent the perimeter of the rectangle
MaRussiya [10]
If I understand the problem correctly, here's the answer:
2 (3x+6) + 2 (2x+4)=94
6x+12+4x+8=94
10x+20=94
10x=74
X=74/10
X=37/5
8 0
4 years ago
Read 2 more answers
Interpret the coefficient PayDay, 96.68. If you were part of the analytics team at Caesars, how would you explain this coefficie
taurus [48]

Answer:

Step-by-step explanation:

solution attached below

3 0
3 years ago
The height of a toy rocket that is shot in the air with an upward velocity of 48 feet per second can be modeled by the function
NikAS [45]

Answer:

maximum height reached = 35 feet

and f(t) = 48t-16.07t^{2}

Step-by-step explanation:

writing linear motion equations

s = ut + \frac{1}{2}at^{2}

where s is the total displacement, u the initial velocity, t the time travelled, and a is the acceleration.

given u = 48 ft/s, and a = acceleration due to gravity g = -9.8\frac{m}{s^{2}}

1 m = 3.28 feet therefore g becomes -9.8×3.28\frac{ft}{s^{2}}

here negative sigh comes as acceleration due to gravity is in opposite direction of initial velocity.

therefore f(t) becomes f(t) = 48t-16.07t^{2}

to find max height we should find differentiation of f(t) and equate it to 0

therefore we get 48 = 32.144t

t = 1.49 s

therefore max height f(1.49) = 71.67-36.67 = 35 feet

4 0
3 years ago
Read 2 more answers
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