Find the volume of the cube below.

I need the thing for the square pizza ill give brainlest to who gets its right

baherus [9]

Answer:

A) The square pizza gives you more delicious (XD) pizza. And 24 (225-201) more pizza.

B) There's more crust on the square pizza then on the circle one, according to 60>50!

Step-by-step explanation:

A)First, let's calculate the area of the round pizza.

We need to find out the radius, and radius= $\frac{diameter}{2}$

So radius=16/2, which is 8.

And a circle's area is $\pi r^{2}$ , so the equation for this round pizza is:

$\pi (8)^{2}$

=64 $\pi$

≅201 $inch^{2}$

Second, we calculate the square pizza's area, which is pretty easy since the equation for a square is: $(Side Length)^{2}$ .

So for this square pizza, the area would be:

$(15)^{2}$

=225 $inch^{2}$

Lastly, we compare the two, 225>201, so the square pizza gives you more delicious (XD) pizza. And 24 (225-201) more pizza.

B)So this problem is actually asking you to find the circumference of the circle and perimeter of the square.

Let's start off with the circle, the formula for circumference is:

$\pi (d)$

We already have the d, (diameter), which is 16, so the circumference of this circle pizza is:

16 $\pi$

≅50 inch

Then we find the a square's, the equation for perimeter is:

4 (side length)

=4(15)

=60 inch

So happily, we found out there's more crust on the square pizza then on the circle one, according to 60>50!

<u><em>Hoped I helped! And hope you can get full credit with my will elongated answer XD.</em></u>

6 0

2 years ago

Chapter : Circles 1 question

erica [24]

We can solve this question in 2 ways: either using degrees or converting the degrees into radians.

Since, the question says degrees itself and there is no specification of using radians only, so I have solved it using degrees itself.

Part (a):

Perimeter of sector ORS = 2*Radius + Arc RS = 2*21 + $60* \frac{ \pi }{180} *21 = \frac{ \pi }{3} *21 = 7 \pi$

Part (b):

Area of sector ORS = $\frac{60}{360} * \pi * 21^{2} = \frac{1}{6} * \pi *21*21= \frac{147}{2} \pi$

Area of sector POQ = $\frac{36}{360} * \pi * 14^{2} = \frac{1}{10} * \pi * 196 = \frac{196}{10} \pi$

Thus, area of shaded region
= Area of sector ORS - Area of sector POQ

= $\frac{147}{2} \pi - \frac{196}{10} \pi = \frac{735 - 196}{10} \pi = \frac{539}{10} \pi = 53.9 \pi$

5 0

2 years ago

Which intervals show f(x) decreasing? Check all that apply.

wolverine [178]

The intervals which represents those in which case the function, f(x) is reducing are as follows; [–2.5, –2], [–2, –1.5], [1.5, 2], [2, 2.5].

<h3>Which intervals naming the answer choices show the function f(x) decreasing?</h3>

It follows from the complete task content that the x-intervals between which the function value of f(x) is reducing are to be identified from the graph as attached.

On this note, by observation on the graph, it follows that from between the interval; [–2.5, –2], the function f(x) is decreasing.

Also, between the interval; [–2, –1.5], the function f(x) is decreasing.

Also, between the interval; [1.5, 2], the function f(x) is decreasing.

Also, between the interval; [2, 2.5], the function f(x) is decreasing.

Remark: The answer choices are as follows; [–2.5, –2] [–2, –1.5] [–1, 1] [1.5, 2] [2, 2.5) [2.5, 3]